Multiply the numbers
4 + 3 . 7
Then 4 + 21
= 25
9514 1404 393
Answer:
23, 49
Step-by-step explanation:
Let s represent the smaller of the two numbers. Then the larger is s+26, and the sum is ...
s + (s+26) = 72
2s = 72 -26
s = (72 -26)/2 = 23
Then the larger number is
s +26 = 49
The two numbers are 23 and 49.
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The reason we wrote the solution this way is to show you that the smaller number is half the difference between the given sum (72) and difference (26). This is the generic solution to a "sum and difference" problem. The smaller number is always half the difference of the give sum and difference. (Similarly, the larger is always half the sum of the given sum and difference.)
That is, the two numbers are always half the sum ± half the difference:
72/2 ± 26/2 = {36+13, 36-13} = {49, 23}
Answer:
x = 7, y = 2
Step-by-step explanation:
I assume it is 3/(x-7) + 2.
When x = 7, there is an asymptote because it is undefined.
When y = 2, there is also one, because 3/(x-7) is never 0.
These are the only ones.
The different between n and 15 is 5 in an algebraic expression would be n-16=5
the solution would be n=21
V = length times width times height
V = 45 * 12 * 10
V = 5400
Hope this helps
