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andriy [413]
3 years ago
5

HELP PLZzzzzzzzzzzzzzz!

Mathematics
2 answers:
faltersainse [42]3 years ago
6 0
D!!

The figure was moved over by positive one on the x axis and by negative 6 on the y axis! :) hope this helps!!
nata0808 [166]3 years ago
5 0

Answer:

D (x,y) ---> (x + 1, y - 6)

Step-by-step explanation:

The triangle in blue moves 1 unit to the right, and 6 units down.

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Which function is a horizontal translation of the parent quadratic function
alexandr1967 [171]

Answer:

C

Step-by-step explanation:

Given f(x) then f(x + a) represents a horizontal translation of f(x)

• If a > 0 then a shift to the left of a units

• If a < 0 then a shift to the right of a units

Thus

g(x) = (x - 4)² represents a horizontal translation to the right of f(x) by 4 units.

8 0
3 years ago
What’s the answer to this problem???
Snowcat [4.5K]
Rewrite the equation into slope intercept form:
8y = -5x+16

divide everything by 8 to get just y
y = -5/8x+2

 the slope = -5/8
8 0
3 years ago
Need Help Badly!!!!!! The dot plot below shows the number of books 26 students read in a month: Dot plot labeled Number of Books
algol13
The dot plot below shows the number of books 26 students read in a month:



<span>Is the median or the mean a better center for this data and why? help plz

</span>
7 0
3 years ago
Help QUICKLY.
mel-nik [20]

Hope this helps!!!!!!!!!

3 0
3 years ago
Triangle ABL is an isosceles triangle in circle A with a radius of 11, PL = 16, and ∠PAL = 93°. Find the area of the circle encl
katovenus [111]

Answer:

The area of the circle enclosed by line PL and arc PL is approximately 37.62 square units

Step-by-step explanation:

The given parameters in the question are;

The radius of the circle, r = 11

The length of the chord PL = 16

The measure of angle ∠PAL = 93°

The segment of the circle for which the area is required = Minor segment PL

The shaded area of the given circle is the minor segment of the circle enclosed by line PL and arc PL

The area of a segment of a circle is given by the following formula;

Area of segment = Area of the sector - Area of the triangle

In detail, we have;

Area of segment = Area of the sector of the circle that contains the segment) - (Area of the isosceles triangle in the sector)

Area of a sector = (θ/360)×π·r²

Where;

r = The radius of the circle

θ = The angle of the sector of the circle

Plugging in the the values of <em>r</em> and <em>θ</em>, we get;

The area of the sector enclosed by arc PL and radii AP and AL = (93°/360°) × π × 11² ≈ 98.2 square units

Area of a triangle = (1/2) × Base length × Height

Therefore;

The area of ΔAPL = (1/2) × 16 × 11 × cos(93°/2) ≈ 60.58 square units

∴ The area of the segment PL ≈ (98.2 - 60.58) square units = 37.62 square units

Therefore, the area of the shaded segment PL ≈ 37.62 square units

More examples on area of a shaded segment can be found here:

brainly.com/question/22599425

8 0
2 years ago
Read 2 more answers
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