Answer:
13g +6
Step-by-step explanation:
3(6g+2) -5g
Distribute
18g +6 - 5g
Combine like terms
13g +6
1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
Answer:
n+4=32
Step-by-step explanation:
The initial number n gets additional 4 students making the new total number of students to be 32. Therefore, this situation can be represented as
n+4=32
To get the actual number of students before the additio, we make n the subject of formula hence
n=32-4
n=28
Therefore, the initial number was 28 and the equation is n+4=32
Since no choices were provided, the equation that can be modified is n+4=32
Answer:
y=4
Step-by-step explanation:
2(y+1)-2=4+y
2y+2-2=4+y
2y=4+y
2y-y=4
y=4
Answer: d
Step-by-step explanation:
