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3 years ago

How do you solve 2(y + 1) – 2 = 4 + 2y - y

Mathematics

2 answers:

pshichka [43]3 years ago

8 0

Answer:

y=4

Step-by-step explanation:

So first of all you do distrabutive property when you do that you get 2y+2-2=+2y then you combine the like terms than when you do that you should get y=4

I hope this helps!

Elina [12.6K]3 years ago

7 0

Answer:

y=4

Step-by-step explanation:

2(y+1)-2=4+y

2y+2-2=4+y

2y=4+y

2y-y=4

y=4

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The price of a buffet lunch is $14.80 per adult and $12 per children. William paid a total of $95.2 for a group of m adults and

lianna [129]

Answer:

$14.80(m) + $12(n) = $95.2

Solved:

$14.80(4) + $12(3) = $95.2

Step-by-step explanation:

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3 years ago

Read 2 more answers

Answer my questions plz help

coldgirl [10]

9514 1404 393

Answer:

a = -2/3, b = 8, c = -24
y-intercept: (0, -24)
x = -b/(2a) = -8/(2(-2/3)) = 8(4/3)
x = 6
DOWN
Max: (6, 0)
Vertex: (6, 0)
Domain: {x | x ∈ ℝ}
Range: {x | x ≤ 0}

Step-by-step explanation:

To find a, b, c, compare the given function to ...

f(x) = ax² +bx +c

You will see that ...

a = -2/3
b = 8
c = -24

The y-intercept is the function value for x=0. It is the constant term:

y-intercept = f(0) = -24

Use the above values of a, b to find the line of symmetry.

$x = \dfrac{-b}{2a}=\dfrac{-8}{2\cdot\dfrac{-2}{3}}=8\cdot\dfrac{3}{4}=6$

Per the calculation, the line of symmetry is ...

x = 6

The negative leading coefficient tells you the parabola opens DOWN.

Because it opens down, the vertex at (6, 0) is a Maximum.

As with any polynomial, the domain is "all real numbers", hence any x that is an element of Reals.

The range is all values below the vertex (including the vertex), so is ...

x ≤ 0

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