First, find the area of each of the prisms sides
5 by 5.5 = 27.5
3 by 5.5 = 16.5
4 by 3 cut in half = 6 (theres 2 of thoses so 12)
4 by 5.5 = 22
Add up the products and the surface area is 78 units
Post brainliest if this helped :)
Answer:
- (-16x² +10x -3) +(4x² -29x -2)
- (2x² -11x -9) -(14x² +8x -4)
- 2(x -1) -3(4x² +7x +1)
Step-by-step explanation:
I find it takes less work if I can eliminate obviously wrong answers. Toward that end, we can consider the constant terms only:
- -3 +(-2) = -5 . . . . possible equivalent
- -10 -5 = -15 . . . . NOT equivalent
- 3(-5) -2(5) = -25 . . . . NOT equivalent
- -9 -(-4) = -5 . . . . possible equivalent
- -7 -(-5) = -2 . . . . NOT equivalent
- 2(-1) -3(1) = -5 . . possible equivalent
Now, we can go back and check the other terms in the candidate expressions we have identified.
1. (-16x² +10x -3) +(4x² -29x -2) = (-16+4)x² +(10-29)x -5 = -12x² -19x -5 . . . OK
4. (2x² -11x -9) -(14x² +8x -4) = (2-14)x² +(-11-8)x -5 = -12x² -19x -5 . . . OK
6. 2(x -1) -3(4x² +7x +1) = -12x² +(2 -3·7)x -5 = -12x² -19x -5 . . . OK
All three of the "possible equivalent" expressions we identified on the first pass are fully equivalent to the target expression. These are your answer choices.
<h3>
Answer: 30.78181 meters</h3>
The value is approximate. Round that however you need to.
========================================================
Explanation:
- lowercase a = side opposite angle uppercase A
- lowercase b = side opposite angle uppercase B
- b = AC
Using the law of sines, we can say:
a/sin(A) = b/sin(B)
45/sin(30) = b/sin(20)
b/sin(20) = 45/sin(30)
b = sin(20)*45/sin(30)
b = 30.78181 approximately
You'll need to make sure your calculator is in degree mode.
Answer:
60.2 m
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you ...
Tan = Opposite/Adjacent
The width of the river is the side of a right triangle opposite the angle of 76°. The 15 m distance is the length of the side adjacent to the measured angle. So, we have ...
tan(76°) = width/(15 m)
Multiplying by 15 m, we get ...
width = (15 m)tan(76°) ≈ 60.2 m
The width of the river is about 60.2 m.
