Answer:
7
Step-by-step explanation:
Answer:
Vertex form
y = -4(x + 3)^2 + 10
Standard form;
y = -4x^2-24x - 26
Step-by-step explanation:
Mathematically, we have the vertex form as
y = a(x-h)^2 + k
(h,k) represents the vertex
We have h as -3 and k as 10
y = a(x+3)^2 + 10
To get a, we substitute any of the points
Let us use (-1,-6)
-6 = a(-1+3)^2 + 10
-6-10 = 4a
4a = -16
a = -16/4
a = -4
So we have the equation as;
y = -4(x+3)^2 + 10
For the standard form;
We expand the vertex form;
y = -4(x + 3)(x + 3) + 10
y = -4(x^2 + 6x + 9) + 10
y = -4x^2 - 24x -36 + 10
y = -4x^2 -24x -26
The area of D is given by:
The average value of f over D is given by:
![\frac{1}{ \frac{343}{3} } \int\limits^7_0 \int\limits^{x^2}_0 {4x\sin(y)} \, dydx = -\frac{3}{343} \int\limits^7_0 {4x\cos(x^2)} \, dx \\ \\ =-\frac{3}{343} \int\limits^{49}_0 {2\cos(t)} \, dt=-\frac{6}{343} \left[\sin(t)\right]_0^{49} \, dt=-\frac{6}{343}\sin49](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%20%5Cfrac%7B343%7D%7B3%7D%20%7D%20%20%5Cint%5Climits%5E7_0%20%20%5Cint%5Climits%5E%7Bx%5E2%7D_0%20%7B4x%5Csin%28y%29%7D%20%5C%2C%20dydx%20%20%3D%20-%5Cfrac%7B3%7D%7B343%7D%20%20%5Cint%5Climits%5E7_0%20%7B4x%5Ccos%28x%5E2%29%7D%20%5C%2C%20dx%20%20%5C%5C%20%20%5C%5C%20%3D-%5Cfrac%7B3%7D%7B343%7D%20%5Cint%5Climits%5E%7B49%7D_0%20%7B2%5Ccos%28t%29%7D%20%5C%2C%20dt%3D-%5Cfrac%7B6%7D%7B343%7D%20%5Cleft%5B%5Csin%28t%29%5Cright%5D_0%5E%7B49%7D%20%5C%2C%20dt%3D-%5Cfrac%7B6%7D%7B343%7D%5Csin49)
According to the information you gave me I believe it is "y", as it complicates it and it's a term?
If I missed the question please let me know
