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lisov135 [29]
3 years ago
10

If Given:

Mathematics
1 answer:
sasho [114]3 years ago
6 0
C i think that would be the answer

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Solve for the equation below<br><br> 4x^n + x^4n = ?
slavikrds [6]
4x + 6 = -10<span>Simplifying 4x + 6 = -10 Reorder the terms: 6 + 4x = -10 Solving 6 + 4x = -10 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + 4x = -10 + -6 Combine like terms: 6 + -6 = 0 0 + 4x = -10 + -6 4x = -10 + -6 Combine like terms: -10 + -6 = -16 4x = -16 Divide each side by '4'. x = -4 Simplifying x = -4</span>
7 0
3 years ago
Mathematics question help
Nat2105 [25]

Distance Formula: \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2}

Point 1: (9,0)

Point 2: (5,-8)

D = sqrt[ (5 - 9)^2 + (-8 - 0)^2 ]

D = sqrt[ (-4)^2 + (-8)^2 ]

D = sqrt[ 16 + 64]

D = sqrt(80)

Hope this helps!

4 0
3 years ago
Read 2 more answers
HELP PLEASE!!!!!!! Asap Giving out brainliest!<br> Which of the following has the greatest value?
Jlenok [28]
1/3^-2

You flip the denominator and the numerator to make the 3^-2 positive. 

3^2/1= 3^2= 9 

1/2^-3 

2^3/1= 2^3= 8 

I can already tell you that the negative exponents are not going to be as high in value. 

3^-2= 1/3^2= 1/9
2^-3= 1/2^3= 1/8

1/3^-2 (the first option) <=== the highest in value

I hope this helps!
~kaikers
6 0
3 years ago
Which equation can be simplified to find the inverse of y = 5x2 + 10?
zmey [24]

f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10

Step-by-step explanation:

interchanging the variables

x = 5y^2 + 10

5y^2 +10 = x

5y^2 = x - 10

dividing by 5

5y^2/5 = x/5 + -10/5

y^2 = x/5 + - 10/5

y^2 = x/5 - 2

y = 5 (x-10) 0/5 (sq.rt)

g(5x^2 + 10) = 5x/5

g(5x^2 + 10) = x

f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10

5 0
3 years ago
Read 2 more answers
Hey need help with some homework my teacher did not explain this very well so could you help me answer it and explain how iis do
Diano4ka-milaya [45]
<span>y in (-oo:+oo)

(3*y+6)/11 = -9 // + 9

(3*y+6)/11+9 = 0

(3*y+6)/11+(9*11)/11 = 0

3*y+9*11+6 = 0

3*y+105 = 0

(3*y+105)/11 = 0

(3*y+105)/11 = 0 // * 11

3*y+105 = 0

3*y+105 = 0 // - 105

3*y = -105 // : 3

y = -105/3

y = -35

y = -35</span>
7 0
3 years ago
Read 2 more answers
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