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3 years ago

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Which number is between 0.5 and 5/8 A) 1/4 B) 8/28 C) 9/16 D) 19/28

2 answers:

Andru [333]3 years ago

8 0

I think a but not sure but i hope i helped :D

Sedaia [141]3 years ago

7 0

First, let's eliminate the ones that are incorrect. So, we have eliminated A and B automatically, because it is more obvious than the other two.
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Ok, so C) is correct, and 0.5 = 8/16, so 9/16 is correct.
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Glad I could help, and good luck.
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Last question for Jim Thompson Geometry homework

Luba_88 [7]

<h3>Answers:</h3>

Reason 1: <u>Given</u>
Reason 3: <u>Similar because of SAS</u>

==============================================

Explanation:

At the top of the proof, your teacher states "Given" followed by the relevant useful info. We simply repeat that info word for word as statement 1. This is how all proofs start out. We start with what we're given and try to build toward what we want to prove.

So this is why <u>reason 1 is "given"</u>. Reason 2 is "given" also. When your teacher gives multiple statements like this, it's handy to break them up into the smallest pieces possible.

--------------------

<u>For reason 3, we use the SAS Similarity</u> rule here because we have congruent angles LPN and LNM (both 90 degrees each) and the sides are proportional due to the statement $\frac{PN}{NM} = \frac{LP}{LN}$

Notice how statement 3 builds entirely off from what statements 1 and 2 set up.

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2 years ago

5) Placido pulls a rope attached to a wagon through a pulley at a rate of q m/s. With dimension as in Figure 5:

Damm [24]

The formula for the speed of the wagon can be found by using Pythagoras theorem, and chain rule of differentiation.

$(a) \ \mathrm{The \ speed \ of \ the \ wagon} , \ \dfrac{dx}{dt} = q -\dfrac{x}{\sqrt{x^2+ 5.76}}$

(b) When <em>x </em>= 0.6 and q = 0.5 m/s, the speed of the wagon is approximately <u>0.243 m/s</u>.

Reasons:

(a) The distance from the cart to the pulley, <em>r</em> is given by Pythagoras's

theorem as follows;

r = √((3 - 0.6)² + x²) = √(2.4² + x²)

The speed of the wagon = $\mathbf{\dfrac{dx}{dt}}$

The speed of the rope, q = $\mathbf{\dfrac{dr}{dt}}$

By chain rule, we have;

$\dfrac{dr}{dt} = \mathbf{\dfrac{dr}{dx} + \dfrac{dx}{dt}}$

$\dfrac{dr}{dx} = \dfrac{x}{\sqrt{x^2+ 5.76}}$

Therefore;

$\dfrac{dr}{dt} = q =\dfrac{x}{\sqrt{x^2+ 5.76}}+ \dfrac{dx}{dt}$

$\mathrm{The \ speed \ of \ the \ wagon} , \ \dfrac{dx}{dt} = \underline{ q -\dfrac{x}{\sqrt{x^2+ 5.76}}}$

(b) The speed of the wagon when <em>x</em> = 0.6 if q = 0.5 m/s is given as follows;

$\dfrac{dx}{dt} = 0.5 -\dfrac{0.6}{\sqrt{0.6^2+ 5.76}} =\sqrt{\dfrac{1}{17} } \approx 0.243$

The speed of the wagon when <em>x </em>= 0.6 and q = 0.5 m/s, $\dfrac{dx}{dt}$ ≈ <u>0.243 m/s</u>

Learn more here:

brainly.com/question/17081984

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2 years ago

Suppose that weight of adolescents is being studied by a health organization and that the accompanying tables describes the prob

svet-max [94.6K]

Answer:

<em>hello your question lacks some information attached below is the complete question</em>

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3 years ago

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Step-by-step explanation:

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What is 1 and 2/5× 7

OleMash [197]

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3 years ago

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