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3 years ago

Which is the product of 14 and 3/7

Mathematics

2 answers:

nasty-shy [4]3 years ago

4 0

6

3/7 x 14/1 =6
This could be done with a Calculator

zysi [14]3 years ago

4 0

Answer: 42/7 = 6

Multiply Numerator by Numerator

14*3=42

Multiply Denominator by Denominator

1*7=7

Get your answer

42/7

Divide

42/7=6

Final answers

42/7 or 6

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Alisiya [41]

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Step-by-step explanation:

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Elodia [21]

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Step-by-step explanation:

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Elanso [62]

$\bf \textit{Logarithm Change of Base Rule}
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and you can just plug that in your calculator.

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3 years ago

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Use the discriminant to determine what type of roots the equations will have, and categorize the equations according to their ro

topjm [15]

Step-by-step explanation:

The discriminant of the quadratic equation $ax^2+bx+c=0$ :

$\Delta=b^2-4ac$

If Δ < 0, then the equation has two complex roots $x=\dfrac{-b\pm\sqrt\Delta}{2a}$

If Δ = 0, then the equation has one repeated root $x=\dfrac{-b}{2a}[/tex If Δ > 0, then the equation has two discint roots [tex]x=\dfrac{-b\pm\sqrt\Delta}{2a}$

$1.\ x^2-4x+2=0\\\\a=1,\ b=-4,\ c=2\\\\\Delta=(-4)^2-4(1)(2)=16-8=8>0,\ \bold{two\ distinct\ roots}\\\sqrt\Delta=\sqrt8=\sqrt{4\cdot2}=2\sqrt2\\\\x=\dfrac{-(-4)\pm2\sqrt2}{2(1)}=\dfrac{4\pm2\sqrt2}{2}=2\pm\sqrt2\\\\==============================\\\\2.\ 5x^2-2x+3=0\\\\a=5,\ b=-2,\ c=3\\\\\Delta=(-2)^2-4(5)(3)=4-60=-56$

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$7.\ 4x^2+11=0\qquad\text{subtract 11 from both sides}\\\\4x^2=-11\qquad\text{divide both sides by 4}\\\\x^2=-\dfrac{11}{4}\to x=\pm\sqrt{-\dfrac{11}{4}}\\\\x=\pm\dfrac{\sqrt{11}}{2}\ i,\ \bold{two\ complex\ roots}$

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3 years ago

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Only 30 minutes please help

andrezito [222]

Answer:

B, and i don't for the second one

Step-by-step explanation:

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