Answer:
![y\in (-\infty ,5]](https://tex.z-dn.net/?f=y%5Cin%20%28-%5Cinfty%20%2C5%5D)
Step-by-step explanation:
In this problem, we need to write "Twenty times y is at most 100 in interval notation
".
20 times y means, 20y
Atmost means an inequality which is ![\le](https://tex.z-dn.net/?f=%5Cle)
ATQ,
![20\times y\le 100](https://tex.z-dn.net/?f=20%5Ctimes%20y%5Cle%20100)
i.e.
![20y\le 100\\\\y\le 5](https://tex.z-dn.net/?f=20y%5Cle%20100%5C%5C%5C%5Cy%5Cle%205)
We can also write it as :
![y\in (-\infty ,5]](https://tex.z-dn.net/?f=y%5Cin%20%28-%5Cinfty%20%2C5%5D)
Hence, the required interval notation is
.
63 = 0.63×10² = 126/2 = 3×21 = √3969 = 77₈
The last is as a base-8 number.
Answer:
1 minutes 33 seconds
Step-by-step explanation:
28 * 60 seconds = 1680 seconds
1680 / 18 = 93.3 seconds or just about 1 minutes and 33 seconds per problem
Answer:
You too
Step-by-step explanation:
I don't know either, so we are in the same boat.
74% means 0.74
"of" means "times"
So, 128 = 0.74 times (the number)
Divide each side of this equation by 0.74 :
128/0.74 = the number
<em>172.973</em> (rounded) = the number