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Romashka [77]
3 years ago
12

Solve for x in the equation 2/5x = 12

Mathematics
1 answer:
-BARSIC- [3]3 years ago
6 0
The correct answer is D.
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Please solve this system of equations.<br> 5x-2y=9<br> 12x-8y=4
sp2606 [1]

Answer:

(4,11/2)

Step-by-step explanation:

5x-2y=9

12x-8y=4

A quick look will tell us that neither the x- nor the y- coefficient is the same in both equations, so combining the two by addition or subtraction. We can see that 2 is a multiple of 8, since 2 x 4 = 8. We should multiply the first equation by 4.

4(5x-2y=9)

Now we need to decide if we should add or subtract the equations.

20x-8y=36

12x-8y=4

Since we need to have a -8 and a +8 to eliminate the variables, we should subtract them. Change all the signs of the second equation and combine.

20x-8y=36

-12x-8y=4

----------------

8x=32

Divide both sides by 8 to get the x-value:

\frac{8x}{8} = \frac{32}{8}

x=4

Now that we have our x-value, we need to plug in the y-value.

5x-2y=9

5(4)-2y=9

20-2y=9

-2y=-11

y=11/2

So our solution is (4,11/2)

Let's check our work.

5x-2y=9

5(4)-2(11/2)=9

20-22/2=9

20-11=9

9=9

12x-8y=4

12(4)-8(11/2)=4

48-88/2=4

48-44=4

4=4

Our solution is correct.

4 0
3 years ago
Read 2 more answers
Please help, thank you!!
Alexxx [7]

Answer:

\sf \dfrac{Area\:of\: \triangle\: AEG}{Area \: of \: quadrilateral\:EGBH}=\dfrac{1}{7}

Step-by-step explanation:

If G is the midpoint of CD, and AC is parallel to DB, then AC = DH.

Therefore, G is the midpoint of AH and ΔACE is similar to ΔDBE.

As AC : DB = 1 : 3

⇒ Area of ΔACE : Area of ΔDBE = 1² : 3² = 1 : 9

We are told that Area ΔACE = Area ΔAEG.

⇒ Area ΔACG = 2 × Area ΔACE

As AC = DH, and G is the midpoint of CD:

⇒ ΔACG ≅ ΔHDG

⇒ Area ΔHDG = 2 × Area ΔACE

Area of quadrilateral EGHB = Area of ΔDBE - Area ΔHDG

                                              = Area of ΔDBE - 2 × Area of ΔACE

Therefore:

\sf \implies \dfrac{Area\:of\: \triangle\: AEG}{Area \: of \: quadrilateral\:EGBH}

\sf \implies \dfrac{Area\:of\: \triangle\: ACE}{Area \: of \: \triangle\:DBE - 2 \times Area\:of\: \triangle ACE}

Using the ratio of Area ΔACE : Area ΔDBE =  1 : 9

\implies \sf \dfrac{1}{9-2}

\implies \sf \dfrac{1}{7}

3 0
2 years ago
Read 2 more answers
Divide. Write your answer in simplest form.<br> 6.4 divided by (-3.2)
Ulleksa [173]

Answer:

6.4/-3.2=-3.2 is a required answer.

6 0
3 years ago
A square has an area of 36cm2. What is the perimeter
lesya [120]
What times what = 36 like two of the same numbers. then multiply that number by 4 for the number of sides and u get the perimiter. (sry if confusing so ill explain that 6×6=36)
7 0
3 years ago
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You plan to spend no more than 2 hours baking all the side dishes. If you
GaryK [48]

Answer:

10 minuts

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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