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ladessa [460]
3 years ago
6

Tomas has a garden with a length of 2.45 meters and a width of 5/8 meters. Use benchmarks to estimate the area and perimeter of

the garden?
Mathematics
2 answers:
Alchen [17]3 years ago
5 0

Answer: The area is  1 1/4. The perimeter is 6.

Step-by-step explanation: 2.45 is about 2.5.   5/8 is about 1/2.  To find the area we need to multiply length times width.  2.5 is  2 and 1/2 which is 5/2. 5/2 times 1/2 is 5/4. To simplify it divide 5 by 4 which is 1 with remainder 1. 5/4 is 1 1/4. Therefore the area is 1 1/4 meters squared. To find the perimeter we have to add length + length + width + width. . 2.5 is the same thing as 2 1/2.  5/8 is about 1/2 if we use benchmarks.     2 1/2 + 2 1/2 +  + 1/2 + 1/2 is 6. The perimeter is 6.

Degger [83]3 years ago
5 0
The answer is 11/4 i did the math and got this
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Step-by-step explanation: Pic is attached. Hope this helps. Sorry for the bad handwriting, I'm writing with a mouse.

5 0
3 years ago
What is the <img src="https://tex.z-dn.net/?f=%5Csqrt%7B10%7D" id="TexFormula1" title="\sqrt{10}" alt="\sqrt{10}" align="absmidd
morpeh [17]
6.32455532 is what my calculator says.
4 0
3 years ago
A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions
faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3><u>Solution:</u></h3>

Given that  

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

<em><u>The area of rectangle is given as:</u></em>

\text {Area of rectangle }=length \times width

Area of rectangular parking lot = length of rectangular parking plot \times width of the rectangular parking

\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}

But it is given that Area of rectangular parking lot = 15000 square feet

\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}

Solving the above quadratic equation using quadratic formula

<em><u>General form of quadratic equation is  </u></em>

{ax^{2}+\mathrm{b} x+\mathrm{c}=0

And quadratic formula for getting roots of quadratic equation is

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}

\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet  

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0
3 years ago
3(x−7)+20=12+2(x−3). Pls help quickly
scZoUnD [109]

Step-by-step explanation:

3x-21+20=12+2x-6

3x-1= 6+2x

3x-2x=6+1

x=7

3 0
3 years ago
HELLP anyone know the answer?!
katovenus [111]

Answer: 212998.58

Step-by-step explanation:

plz mark me brainliest

if the price increases 6% every year for 7 years you would have to multiply 7 by 6 which is 42 so you have to add 42% to 149,999 which is 212998.58.

6 0
3 years ago
Read 2 more answers
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