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ladessa [460]
3 years ago
6

Tomas has a garden with a length of 2.45 meters and a width of 5/8 meters. Use benchmarks to estimate the area and perimeter of

the garden?
Mathematics
2 answers:
Alchen [17]3 years ago
5 0

Answer: The area is  1 1/4. The perimeter is 6.

Step-by-step explanation: 2.45 is about 2.5.   5/8 is about 1/2.  To find the area we need to multiply length times width.  2.5 is  2 and 1/2 which is 5/2. 5/2 times 1/2 is 5/4. To simplify it divide 5 by 4 which is 1 with remainder 1. 5/4 is 1 1/4. Therefore the area is 1 1/4 meters squared. To find the perimeter we have to add length + length + width + width. . 2.5 is the same thing as 2 1/2.  5/8 is about 1/2 if we use benchmarks.     2 1/2 + 2 1/2 +  + 1/2 + 1/2 is 6. The perimeter is 6.

Degger [83]3 years ago
5 0
The answer is 11/4 i did the math and got this
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Does anybody know this what the answer to this question is please?
Svetlanka [38]

Answer:

The answer is option 3.

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6 0
3 years ago
Which line has the equation 2x - 3y = 6?<br> (Please explain how you got your answer)
notsponge [240]
First, isolate y:
2x - 3y = 6
-3y = -2x + 6
3y = 2x - 6
y = 2/3x - 2
That means that the line passes through the point (0, -2) and has a positive slope of 2/3. So it would be choice A because the line in choice A passes through the point (1, -2) and has a positive slope. Choice D also passes through the point (0, -2) but has a negative slope so it cannot be the correct answer.
Choice A is correct.
3 0
3 years ago
PLEASE ANSWERRRRRRRRRRRRRRRRRRRRRRRR
tekilochka [14]

Answer:

a=11, b=53

Step-by-step explanation:

y=ax+b

x=1, y=64 -> 64=a+b

x=2, y=75 -> 75=2a+b

75-64=a, a=11, b=53

All the other points obey this rule.

8 0
3 years ago
Read 2 more answers
Can someone help me factor 4x^2-36x+32? Help!!
S_A_V [24]
4 times (x^2-9x+8). Hope that helps!
5 0
3 years ago
The coordinate plane below represents a city. Points A through F are schools in the city.
astra-53 [7]
Part A:
<span>a system of inequalities that only contain points D and E in the overlapping shaded regions is
5y + 2x > 12
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Part B:
To verify that points D and E are solutions to the system of inequalities, we plug in the coordinate points of points D and E into the system of ineaqualities.

Part C:
</span>To <span>identify the schools that Timothy is allowed to attend we plug in the coordinate values of the points to see which satisfies the inequality y < 3x - 3. Thus Timothy is allowed to attend schools C and F.</span>
7 0
3 years ago
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