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3 years ago

The inverse of x - y is

2 answers:

7 0

Yes, The inverse of y = -x is itself.

Switch the x's and y's and solve for y.

Switch x's and y's: X= - y

Divide both sizes by : - 1 and - x = y

So the inverse of y= -x is y = x.

lapo4ka [179]3 years ago

6 0

Swap the domain and range from the original question

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sally is on a scavenger hunt. a clue tells her to walk 100 steps due south from the starting point and then walk west when she g

Sophie [7]

Answer:

She should take 112 steps west

Step-by-step explanation:

* Lets explain the relation between the four directions

- North and South on the same line by in opposite directions

- East and West on the same line by in opposite directions

- East and West are perpendicular to the North and South

* Now lets study the situation i the problem

- Sally 100 steps due to South from the starting point

- Then she walk West when she gets the next clue

- The distance between her starting point and ending point is 150 steps

∵ The South is perpendicular to the West

- Lets consider her trip is a right angle triangle ABC, where AB

her steps South and BC her steps West and AC the distance

between her starting point and ending point

∵ AB = 100

∵ AC = 150

∵ m∠B = 90°

- By using Pythagoras theorem

∵ BC = √(AC² - AB²)

∴ BC = √(150² - 100²) = 50√5 = 111.8 steps

* She should take 112 steps west

8 0

3 years ago

Given: F(x) = 3x^2+ 1, G(x) = 2x - 3, H(x) = x<br> F(x) + G(x) =

Agata [3.3K]

Answer:

(FoG) -1 (x) = x/5 + 26/5

Step-by-step explanation:

4 0

3 years ago

Is 4/8 bigger or smaller than 1/2

jeka94

There are the same because 4/8 is rudeced to 1/2

8 0

3 years ago

Read 2 more answers

Find the modulus of the complex number 6-2i

Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

$|z|\:=2\sqrt{10}$

Step-by-step explanation:

Given the number

$6-2i$

We know that

$z = x + iy$

where x and y are real and $\sqrt{-1}=i$

The modulus or absolute value of z is:

$|z|\:=\sqrt{x^2+y^2}$

Therefore, the modulus of $6-2i$ will be:

$z=6-2i$

$z=6+(-2)i$

$|z|\:=\sqrt{x^2+y^2}$

$|z|\:=\sqrt{6^2+\left(-2\right)^2}$

$=\sqrt{6^2+2^2}$

$=\sqrt{36+4}$

$=\sqrt{40}$

$=\sqrt{2^2}\sqrt{2\cdot \:5}$

$=2\sqrt{2\cdot \:5}$

$=2\sqrt{10}$

Therefore, the modulus of the complex number 6-2i is:

$|z|\:=2\sqrt{10}$

3 0

2 years ago

Graph x > 2

Andrews [41]

Answer:

Bottom left

Step-by-step explanation:

Because when you draw the graph you see that x is larger than 2 , and 2 is not including in the solution so, we just make a small lines (forget the y-axis).

I hope that it's a clear solution and explanation.

3 0

3 years ago