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2 years ago

If g(x)= x+1/x-2 and h(x)= 4-x, what is the value of (g*h) (-3)

Mathematics

1 answer:

polet [3.4K]2 years ago

8 0

Answer:

14/5.

Step-by-step explanation:

(g*h) ( x) = (x + 1)( 4 - x) / (x - 2)

So (g*h) (-3) = (4 - -3) (-3 + 1) / (-3-2)

= 7 * -2 / -5

= -14/ -5

= 14/5.

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Find the standard form of the equation of the ellipse with the given characteristics. Vertices: (4, 0), (4, 14); endpoints of th

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Answer:

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Step-by-step explanation:

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If we know that $V_{1} (x,y) = (4,0)$ and $V_{2}(x,y) = (4, 14)$ , then the coordinates of the center are, respectively:

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The standard equation of the ellipse is described by the following formula:

$\frac{(x-h)^{2}}{a^{2}}+ \frac{(y-k)^{2}}{b^{2}} = 1$

Where:

$h$ , $k$ - Coordinates of the center of the ellipse.

$a$ , $b$ - Length of the orthogonal semiaxes.

If we know that $h = 4$ , $k = 7$ , $a = 3$ and $b = 7$ , then the standard form of the ellipse is:

$\frac{(x-4)^{2}}{9} + \frac{(y-7)^{2}}{49} = 1$

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Answer:

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to double check your work just multiply 7.1 by the square root of 2 and you'll get close to 10. (because the answer is rounded and not exact.)

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