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3 years ago

For which values of x does 2x^2=10x?

Mathematics

2 answers:

dalvyx [7]3 years ago

8 0

Answer:

The values of x for which it is true that $2x^2=10x$ are:

$x = 0$ and $x = 5$

Step-by-step explanation:

We have the following equation

$2x^2=10x$

To solve the equation subtract 10x on both sides of the equation

$2x^2-10x=10x-10x$

$2x^2-10x=0$

Now take the variable x as a common factor

$2x(x-5)=0$

Then the equation is equal to 0 when x = 0 or when x = 5

$x = 0$ and $x = 5$

Sphinxa [80]3 years ago

7 0

Answer:

x = 0; x = 5

Step-by-step explanation:

2x² = 10x

2x² - 10x = 0

2x(x - 5) = 0

x = 0; x = 5

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A 1year loan at 6% ended up costing $144 in simple interest . How much money was borrowed

Ghella [55]

<span>How much money was borrowed</span> $144/0.06 = $2,400.

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3 years ago

Find the midpoint M of the line segment joining the points S = (-8, 3) and T = (2, -1).

Alex

Step-by-step explanation:

use the midpoint formula

$( \frac{xs + xt}{2} \: \: \frac{ys + yt}{2} )$

substitute into the midpoint formula

$( \frac{ - 8 + 2}{2} \: \: \frac{3 + ( - 1)}{2} )$

solve the above

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$(3 \: \: 1)$

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3 years ago

If y varies directly with x and y = 16 when x = 4, find x when y = 8.

VladimirAG [237]

Answer: X = 2

Step-by-step explanation:

Y & X

Y = KX

K = Y/X = 16/4 = 4

Y= 8

K =4

X=?

X = Y/K

X = 8/4 = 2

7 0

3 years ago

Read 2 more answers

1. Solve for x.

kati45 [8]

This is the answer for the first one

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3 years ago

Read 2 more answers

After the mill in a small town closed down in 1970, the population of that town started decreasing according to the law of expon

wlad13 [49]

Answer:

$P_o = \frac{143000}{e^{-20*0.01303024661}}=110193.69$

And we can round this to the nearest up integer and we got 110194.

Step-by-step explanation:

The natural growth and decay model is given by:

$\frac{dP}{dt}=kP$ (1)

Where P represent the population and t the time in years since 1970.

If we integrate both sides from equation (1) we got:

$\int \frac{dP}{P} =\int kdt$

$ln|P| =kt +c$

And if we apply exponentials on both sides we got:

$P= e^{kt} e^k$

And we can assume $e^k = P_o$

And we have this model:

$P(t) = P_o e^{kt}$

And for this case we want to find $P_o$

By 1990 we have t=20 years since 1970 and we have this equation:

$143000 = P_o e^{20k}$

And we can solve for $P_o$ like this:

$P_o = \frac{143000}{e^{20k}}$ (1)

By 2019 we have 49 years since 1970 the equation is given by:

$98000 = P_o e^{49k}$ (2)

And replacing $P_o$ from equation (1) we got:

$98000=\frac{143000}{e^{20k}} e^{49k} =143000 e^{29k}$

We can divide both sides by 143000 we got:

$\frac{98000}{143000} =0.685 = e^{29k}$

And if we apply ln on both sides we got:

$ln(0.685) = 29k$

And then k =-0.01303024661[/tex]

And replacing into equation (1) we got:

$P_o = \frac{143000}{e^{-20*0.01303024661}}=110193.69$

And we can round this to the nearest up integer and we got 110194.

7 0

3 years ago