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3 years ago

Which plane is parallel to plane LMQ?

Mathematics

1 answer:

GrogVix [38]3 years ago

5 0

Answer:

KJP is the answer, if I'm correct

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Divide. (334)÷(−212) Enter your answer as a mixed number, in simplified form, in the box.

Mandarinka [93]

Answer:

-1.575, or -1 575/1000, or -1 23/40

Step-by-step explanation:

Simplify the problem slightly by prefacing it with " - " as follows:

334

- ----------- = -1.575 = -1 23/40

212

3 0

3 years ago

Read 2 more answers

I need help for solving 4.8(x+4)=2.16

Bas_tet [7]

I hope this helps you

4,8 (x+4)=2,16

48 (x+4)=21,6

x+4=21,6/48

x+4= 0,45

x=0,45-4

x= -3,55

5 0

3 years ago

Read 2 more answers

Please answer all the questions above.

Fed [463]

Answer:

hope it was helpful!! You are welcome to ask any question

7 0

2 years ago

Read 2 more answers

The number y of hits a new website receives each month can be modeled by y = 4070ekt, where t represents the number of months th

makvit [3.9K]

Answer:

k = 0.2645

Step-by-step explanation:

Given model:

y = 4070 $e^{kt}$

y = no. of hits website received = 9000 (in 3rd month)

t= no. of months website has been operational = 3

put in the above equation:

9000 = 4070 $e^{3k}$

$\frac{9000}{4070}$ = $e^{3k}$

$\frac{900}{407}$ = $e^{3k}$

Taking natural logarithm on both sides, we get:

$ln\frac{900}{407}$ = $ln(e^{3k})$

$ln\frac{900}{407}$ = 3k lne

lne=1

$ln \frac{900}{407}$ = 3k

or k = $\frac{1}{3}$ $ln\frac{900}{(407)}$

k = $\frac{1}{3}$ (0.7936)

k = 0.2645

7 0

3 years ago

Find the indicated probability. The weekly salaries of teachers in one state are normally distributed with a mean of $490 and a

Alecsey [184]

Given Information:

Mean weekly salary = μ = $490

Standard deviation of weekly salary = σ = $45

Required Information:

P(X > $525) = ?

Answer:

P(X > $525) = 21.77%

Step-by-step explanation:

We want to find out the probability that a randomly selected teacher earns more than $525 a week.

$P(X > 525) = 1 - P(X < 525)\\\\P(X > 525) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\P(X > 525) = 1 - P(Z < \frac{525 - 490}{45} )\\\\P(X > 525) = 1 - P(Z < \frac{35}{45} )\\\\P(X > 525) = 1 - P(Z < 0.78)\\\\$

The z-score corresponding to 0.78 from the z-table is 0.7823

$P(X > 525) = 1 - 0.7823\\\\P(X > 525) = 0.2177\\\\P(X > 525) = 21.77 \%$

Therefore, there is 21.77% probability that a randomly selected teacher earns more than $525 a week.

How to use z-table?

Step 1:

In the z-table, find the two-digit number on the left side corresponding to your z-score. (e.g 0.7, 2.2, 1.5 etc.)

Step 2:

Then look up at the top of z-table to find the remaining decimal point in the range of 0.00 to 0.09. (e.g. if you are looking for 0.78 then go for 0.08 column)

Step 3:

Finally, find the corresponding probability from the z-table at the intersection of step 1 and step 2.

3 0

3 years ago