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cricket20 [7]
2 years ago
7

If 20 minutes from now the time will be 12 noon what time was it 30 minutes ago​

Mathematics
1 answer:
EastWind [94]2 years ago
4 0
11:10am

20 minutes before 12 noon is 11:40am
30 minutes before 11:40am is 11:10am
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Suppose you are repeating a classic study of starfish and their impact on the ecosystems of tide pools. Using historic data coll
Travka [436]

Answer:

The probability of the number of starfish dropping below 3 is 0.0463.

Step-by-step explanation:

Let X represent the number of starfish in the tide pool.

X follows a Poisson distribution with mean 6.4.

The formula for Poisson distribution is as follows.

P(X=x) = e^{-6.4} * [6.4^{x} / x!] when x = 0, 1, ...

P(X = x) = 0 otherwise

We need to find the probability that the number of starfish in the tide pool drops below 3.

Therefore, the required probability is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X=2)

P(X < 3) = e^{-6.4} + (e^{-6.4}*6.4) + (e^{-6.4}*6.4^{2}/2)

P(X < 3) = 0.00166 + 0.01063 + 0.03403

P (X < 3) = 0.0463

4 0
3 years ago
Factor completely x2 − 36. (1 point)
puteri [66]

Answer:

Solution given:

x²-36

x²-6²

(x+6)(x-6)

is your answer

6 0
3 years ago
Two quantities are related, as shown in the table: x y 2 2 4 5 6 8 8 11 Which equation best represents the relationship? (4 poin
Bogdan [553]
That would be y =3/2 x - 1

Thats the third choice
4 0
3 years ago
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Tunde's cookie shop is having a sale. Marcos
ELEN [110]

Answer:

Each cookie costs $1.30

Step-by-step explanation:

7x+2=11.10

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6 0
3 years ago
What is the value of the correlation coefficient r of the data set?
enyata [817]

The correct option will be:  C) 0.84

<u><em>Explanation</em></u>

Formula for Correlation coefficient :

r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{\sqrt{[n\Sigma x^2-(\Sigma x)^2][n\Sigma y^2-(\Sigma y)^2]}}

First, for each point(x, y), we need to calculate x², y² and xy .

Then, we will find sum all x, y, x², y² and xy, which gives us Σx, Σy, Σx², ∑y² and Σxy

<em>(Please refer to the attached image for the table )</em>

Here we got, ∑x = 44 , ∑y = 183 , ∑x² = 362 , ∑y² = 6575 and ∑xy = 1480

'n' is the total number of data set, which is 7 here.

So, plugging those values into the above formula..........

r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{\sqrt{[n\Sigma x^2-(\Sigma x)^2][n\Sigma y^2-(\Sigma y)^2]}}\\ \\ r=\frac{7(1480)-(44)(183)}{\sqrt{[7(362)-(44)^2][7(6575)-(183)^2]}}\\ \\ r=\frac{10360-8052}{\sqrt{(598)(12536)}}\\ \\ r=\frac{2308}{\sqrt{7496528}}\\ \\ r=0.84

So, the value of the correlation coefficient is 0.84

4 0
3 years ago
Read 2 more answers
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