Can anyone help me this was literally due over a week ago

Mathematics

2 answers:

Virty [35]3 years ago

7 0

Answer:

Step-by-step explanation:

The task is a little not clear .... When I answered on this question earlier, I actually found multiplicative inverse of the product of 1/5 and (2x - 1/5)

But now I can see the question might be to find of The product of multiplicative inverse of 1/5 and (2x - 1/5)

mixer [17]3 years ago

6 0

Answer:

You multiply 5 by 1/5 to get 1. So with 2x, you multiply by 1/(2x) to get 1. That's about all you know, since we only know that x is positive.

Step-by-step explanation:

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Help Plz (Emergency)

kompoz [17]

Answer: s = 36

Step-by-step explanation: The key to solving multistep equations is isolating the variable. This is why I first subtracted 14 on each side. This left me with 1/3s=12. Then, to isolate "s" even more, I didvided by 1/3 on each side. This gave me s = 36 as an answer.

To divide by a fraction, use "keep change flip." Keep the first mumber, change division to multiplication, and flip the fraction. I included a picture of me doing this.

If you have any other questions, please feel free to ask :)

3 0

3 years ago

1274+3599 make a ten or a hundred to add mentally

VladimirAG [237]

Well the answer to 1274 plus 3599 = 4873. but I don't know what you are asking for?

6 0

3 years ago

Read 2 more answers

A trough of water is 20 meters in length and its ends are in the shape of an isosceles triangle whose width is 7 meters and heig

Vaselesa [24]

Answer:

a) Depth changing rate of change is $0.24m/min$ , When the water is 6 meters deep

b) The width of the top of the water is changing at a rate of $0.17m/min$ , When the water is 6 meters deep

Step-by-step explanation:

As we can see in the attachment part II, there are similar triangles, so we have the following relation between them $\frac{3.5}{10} =\frac{a}{h}$ , then $a=0.35h$ .

a) As we have that volume is $V=\frac{1}{2} 2ahL=ahL$ , then $V=(0.35h^{2})L$ , so we can derivate it $\frac{dV}{dt}=2(0.35h)L\frac{dh}{dt}$ due to the chain rule, then we clean this expression for $\frac{dh}{dt}=\frac{1}{0.7hL}\frac{dV}{dt}$ and compute with the knowns $\frac{dh}{dt}=\frac{1}{0.7(6m)(20m)}2m^{3}/min=0.24m/min$ , is the depth changing rate of change when the water is 6 meters deep.

b) As the width of the top is $2a=0.7h$ , we can derivate it and obtain $\frac{da}{dt}=0.7\frac{dh}{dt} =0.7*0.24m/min=0.17m/min$ The width of the top of the water is changing, When the water is 6 meters deep at this rate