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erma4kov [3.2K]
3 years ago
15

What’s the slope of ( 10, 5 ) , ( -8,9 )

Mathematics
1 answer:
kkurt [141]3 years ago
4 0

Answer:

-0.2

Step-by-step explanation:

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Can someone help Me !! Need ASAP
Colt1911 [192]
X=7/5 and 7/5=1.4so x=1.4
6 0
3 years ago
What is the inverse of f(x)=(x+6)2 for x≥–6 where function g is the inverse of function f? g(x)=x√−6, x≥0 g(x)=x−6−−−−√, x≥6 g(x
avanturin [10]

Answer:

g(x)=\sqrt{x}-6, x>=0

Step-by-step explanation:

f(x)=(x+6)^2

To find the inverse function , replace f(x) by y

y=(x+6)^2

Replace x with y and y with x

x=(y+6)^2

Solve the equation for y

take square root on both sides

+\sqrt{x} =y+6

Now subtract 6 from both sides

+\sqrt{x}-6=y

replace y with g(x)

g(x)=\sqrt{x}-6

8 0
4 years ago
Please helppp meeeee!!!!!!
bogdanovich [222]

Answer:

18, 23

Step-by-step explanation:

a. We know that W = 5 and D = 3 so:

P = 3W + D = 3 * 5 + 3 = 18 points

b. We know that P = 50 and D = 14 and that we are solving for W so we get:

50 = 3W + 14

36 = 3W

W = 12 which means the losses are 35 - 12 = 23.

8 0
4 years ago
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Graph f(x) = x2 + 2x - 3, label the function’s x-intercepts, y-intercept and vertex with their coordinates. Also draw in and lab
Semenov [28]
<h2>Answer with explanation:</h2>

The given function : f(x)=x^2+2x-3

Using completing the squares, we have

f(x)=x^2+2x+1-1-3        [∵ (x+1)^2=x^2+2x+1]

f(x)=(x+1)^2-4      (1)

Comparing (1) to the standard vertex form f(x)=(x-h)^2+k , the vertex of function is at (h,k)=(-1,-4)

For x-intercept, put f(x)=0 in (1), we get

0=(x+1)^2-4\\\\\Rightarrow\ (x+1)^2=4    

Square root on both sides, we get

x+1=\pm2\\\\x+1=-2\ or\ \ x+1=2\\\\=x=-3\ \ or\ x=1

∴ x intercepts : x= (-3,0) and (1,0)

For y-intercept put x=0 in (1), we get

f(1)=(1)^2-4=1-4=-3  

∴ y intercept : (0,-3)

Axis of symmetry : \dfrac{-b}{2a}

In f(x)=x^2+2x-3 , a=1 and b=2

Axis of symmetry=\dfrac{-2}{2(1)}=-1

5 0
4 years ago
I need this right now, which 3 are expressions.
Juliette [100K]
The answer is b hopefully I helped
6 0
3 years ago
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