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asambeis [7]
3 years ago
8

What is the inverse of f(x)=(x+6)2 for x≥–6 where function g is the inverse of function f? g(x)=x√−6, x≥0 g(x)=x−6−−−−√, x≥6 g(x

)=x√+6, x≥0 g(x)=x+6−−−−√, x≥−6
Mathematics
1 answer:
avanturin [10]3 years ago
8 0

Answer:

g(x)=\sqrt{x}-6, x>=0

Step-by-step explanation:

f(x)=(x+6)^2

To find the inverse function , replace f(x) by y

y=(x+6)^2

Replace x with y and y with x

x=(y+6)^2

Solve the equation for y

take square root on both sides

+\sqrt{x} =y+6

Now subtract 6 from both sides

+\sqrt{x}-6=y

replace y with g(x)

g(x)=\sqrt{x}-6

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Step-by-step explanation:

z = m - x

Add x to both sides.

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Subtract z from both sides.

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3 years ago
Determine f^-1(2) given the following: f(1 = -3f(2) = -2f(-1) = 2f(3) = -1
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We assume that the function is as follows:

f^{-1_{}}(2)=?

Then, we have that:

f^{-1}(x)=\frac{1}{f(x)}

Thus, if we have that:

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1 year ago
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2 years ago
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