Answer:
Step by Step:
x-2y=4
+2y +2y
x=-2y+4
x-2y=4
-4 -4
x-2y-4=0
+2y +2y
x-4=2y
Divid by 2
1/2x-2= y
x=-2y+4
x=-2(1/2x-2)+4
x=-x+4+4
x=-x+8
+x +x
2x= 8
x=4
y=1/2x-2
y=1/2(4)-2
y=2-2
y=0
(4,0)
Answer:
$100.75
Step-by-step explanation:
422.05 - 106.30 - 310.00 + 95.00 = 100.75
Answer:
The domain of the graph must be
.
Therefore,

Hence, option a is true.
Step-by-step explanation:
From the graph, it is clear that the graph is heading towards positive infinity from x=-4.
The point x=-4 is included in the graph as the starting point of the graph i.e. x=4 is showing a closed circle on x=4, and heading towards positive infinity onward.
i.e. [-4, ∞)
Hence, the domain of the graph must be
.
Therefore,

Hence, option a is true.
To find the answer, set up an equation:

Using this set up we can cross out the units that are on opposite sides of the proportion such as miles and hours, leaving us with the desired units of meters and seconds. Then calculate m/s by multiplying 45 by 1000 meters and then dividing that value by 3600 seconds.
The resulting answer is 45mph = 12.5 m/s
Answer:

Step-by-step explanation:
