T=2π/|b|. The period of an equation of the form y = a sin bx is T=2π/|b|.
In mathematics the curve that graphically represents the sine function and also that function itself is called sinusoid or sinusoid. It is a curve that describes a repetitive and smooth oscillation. It can be represented as y(x) = a sin (ωx+φ) where a is the amplitude, ω is the angular velocity with ω=2πf, (ωx+φ) is the oscillation phase, and φ the initial phase.
The period T of the sin function is T=1/f, from the equation ω=2πf we can clear f and substitute in T=1/f.
f=ω/2π
Substituting in T=1/f:
T=1/ω/2π -------> T = 2π/ω
For the example y = a sin bx, we have that a is the amplitude, b is ω and the initial phase φ = 0. So, we have that the period T of the function a sin bx is:
T=2π/|b|
Answer:
15
Step-by-step explanation:
The answer is D , because if you look on the graph you going to see the Answer in your face
Answer:
Step-by-step explanation:
i think its c
-1/2 x 1/2 = -1x1 / 2x2 = -1/4
The answer is -1/4
