6x+3y=33..........(1)
4x+y=15
y=15-4x.........(2)
substitute value of y from (2) in (1)
6x+3(15-4x)=33
distribute 3 over the bracket
6x+45-12x =33
-6x=33-45
-6x=-12
x=2
plugging this value of x in equation 2 we get
15-4x=y
15-4(2)=y
y=15-8
y=7
Answer is x=2 and y=7
6 + 9x.....a common factor in both terms is 3
3(2 + 3x) <==
Answer:
He needs 7 buckets of cement, and 28 buckets of sane.
Step-by-step explanation:
cement : sand
1:4 = 5
35/5 = 7
7*1=7 . Cement
7*4=28 . Sand
Answer:
216 times smaller, 21600%, the cross section is a rectangle or square
You can use the calculator or 0^2 is 0 x -3 =0 +7 (0) -4 =-4
