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MrRissso [65]
3 years ago
7

use the ruler provided to measure the base of the parallelogram shown to the nearest 0.5 CM which measurement is the closest to

the area of the parallelogram in square centimeters ​

Mathematics
1 answer:
valkas [14]3 years ago
3 0

Answer:

Area of the parallelogram = 21.6 cm²

Step-by-step explanation:

Area of a parallelogram = Base × Height of the side parallel to the base

By using ruler,

Base = 4.8 cm

Height of parallelogram = 4.5 cm

Area of the parallelogram = 4.8 × 4.5

                                           = 21.6 cm²

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(CO6) From a random sample of 68 businesses, it is found that the mean time that employees spend on personal issues each week is
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(1) (4.82, 4.98)

(2) Large sample size

(3) Yes, the temperature is within the confidence interval of (37.40, 37.60)

(4) (15.083, 15.117)

Step-by-step explanation:

Confidence Interval (CI) = mean + or - (t×sd)/√n

(1) mean = 4.9, sd = 0.35, n = 68, degree of freedom = n-1 = 68 - 1 = 67

t-value corresponding to 67 degrees of freedom and 95% confidence level is 1.9958

CI = 4.9 + (1.9958×0.35)/√68 = 4.98

CI = 4.9 - (1.9958×0.35)/√68 = 4.82

CI is (4.82, 4.98)

(2) Error margin = (t-value × standard deviation)/√sample size

From the formula above, error margin varies inversely as the square root of the sample size. Since the relationship between the error margin and sample size is inverse, increase in one (sample size) will conversely lead to a decrease in the other (error margin)

(3) mean = 37.5, sd = 0.6, n= 100, degree of freedom = n-1 = 100-1 = 99

t-value corresponding to 99 degrees of freedom and 90% confidence level is 1.6602

CI = 37.5 + (1.6602×0.6)/√100 = 37.5 + 0.10 = 37.60

CI = 37.5 - (1.6602×0.6)/√100 = 37.5 - 0.10 = 37.40

37.53 is within the confidence interval (37.40, 37.60)

(4) mean = 15.10, sd =0.08, n = 104, degree of freedom = n-1 = 104-1 = 103

t-value corresponding to 103 degrees of freedom and 97% confidence interval is 2.2006

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3 years ago
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Answer:

(x-1)^2+(y-2)^2=6.25

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The equation for a circle is given by:

(x-h)^2+(y-k)^2=r^2

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The center is the red dot, which is (1,2). Thus, h=1 and k=2.

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d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Let (1,2) be <em>x₁ </em>and <em>y₁ </em>and let (2.5,4) be <em>x₂ </em>and <em>y₂. </em>Therefore:

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Thus, r is 2.5.

Plugging these numbers into the equation, we have:

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