To figure ut the roots use the quadratic formula
x = [-b +- sqrt(b^2-4ac)]/2a
x = [-k +- sqrt(k^2-4(1)(5)]/2(1)
x = [-k + sqrt(k^2 - 20)]/2 or [-k - sqrt(k^2 - 20)]/2
So the question says these roots differ by sqrt 61, so let's subtract each
[-k + sqrt(k^2 - 20)]/2 - [-k - sqrt(k^2 - 20)]/2
well the k's cancel in the beginning and we are left with 2sqrt(k^2 - 20)/2, and the 2 on top and bottom reduce to
sqrt(k^2 - 20), so this equals sqrt 61
Set equal and solve
sqrt(k^2 - 20) = sqrt(61)
k^2 - 20 = 61
k^2 = 81, so k = +9 or -9
The greatest value therefore is k = +9.
Answer:
x= 25.
Step-by-step explanation:
To isolate "x", I first moved all terms containing x to the left side of the equation: 0.32x-5=3 (0.4-0.08=0.32). Then moved all terms not containing x to the right side of the equation: 0.32x=8. Finally, I divided 8 by 0.32 which equals 25. Thus, x=25. I hope this helped!
Answer:
3/5
Step-by-step explanation:
1 1/2÷2 1/2
=3/2÷ 2 1/2
=3/2÷5/2
=3/5
Answer:
1224 and 3015
Step-by-step explaination
You have to do 36 lined up with 34 to get 1224
Make sure you add a zero the second time you multiply
For the second promblem, you line up 45 with 67 to get 3015.