All categories

2 years ago

Find the measure of the angle indicated. Assume that lines which appear tangent are tangent.

Mathematics

1 answer:

Tanzania [10]2 years ago

3 0

Answer:

D. 69°

Step-by-step explanation:

I think you divide 222° by 2, which equals 111, then subtract that from 180°, which equals 69°.

You might be interested in

Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

6 0

2 years ago

A new pencil is 19 centimeters long. Levi uses it for a month. The pencil now measures 8 centimeters.

pogonyaev

Answer:

11 cm

Step-by-step explanation:

Given:

Length of new pencil = 19 cm

Length of pencil after using a month = 8 cm

Question asked:

The pencil is centimeters shorter now than when it was new = ?

Solution:

Length of new pencil = 19 cm

Length of pencil after using a month = 8 cm

The pencil is centimeters shorter now than when it was new = 19 cm - 8 cm

= 11 cm

Length of pencil has been used during a month = 11 cm

8 0

3 years ago

The sum of three consecutive even integers is 54. Find all three integers.

matrenka [14]

A good way to find the answer to these questions is to find it algebraically. Let's call the first number 'n'.
n + (n + 2) + (n + 4) = 54
3n + 6 = 54
3n = 48
n = 16
Therefore the numbers are 16, 18, 20

6 0

3 years ago

The graphs below have the same shape. What is the equation of the blue<br> graph?

Harlamova29_29 [7]

Answer:

for this graph the answer is D

7 0

2 years ago

carbon-14 has a half-life of 5730 years. The formula f(t)=(1/2)^t/5730 give the percentage of carbon-14 left in the item after t

andreyandreev [35.5K]

Heyy sorry I need the points

5 0

2 years ago