Answer:
To find the interquartile range (IQR), first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.
Step-by-step explanation:
Answer:
x = 10
Step-by-step explanation:
OA = OD ( both radii of the circle )
OD = OB + BD = x + 16
OB is at right angles to OB ( line from centre to midpoint of chord is right )
Using Pythagoras' identity in right triangle ABO
OA² = OB² + AB² , that is
(x + 16)² = x² + 24²
x² + 32x + 256 = x² + 576 ( subtract x² from both sides )
32x + 256 = 576 ( subtract 256 from both sides )
32x = 320 ( divide both sides by 32 )
x = 10
Answer:
Your smart maybe
Step-by-step explanation:
Answer:
is it 5y/8_5y/16 or 5y/8-5y/16 ?
Step-by-step explanation:
