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Lana71 [14]
4 years ago
14

You take a group of 20 people going to the movies. Kid’s tickets cost $4.-each, and adults tickets $6.-each. Your total cost is

$96.-. The number of kids in your group is.
Mathematics
1 answer:
Sav [38]4 years ago
8 0
A) ....... My little brother got this question and he got 100 on his homework.
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A circular mat has a circumference of 220 centimeters. Find the radius rounded to the nearest whole number.
Papessa [141]
С = 2πr  [π≈3.14]

220 = 2 * 3.14 * r
220 = 6.28r 
r = 220/6.28 ≈ 35 cm  ←  <span>to the nearest whole number.</span>
6 0
3 years ago
PLEASE HELP ASAP 35 PTS
salantis [7]

Answer:

B


Step-by-step explanation:


4 0
3 years ago
Which is a counterexample that shows the statement is false? If you square a number, then the answer is greater than the number.
Iteru [2.4K]

Answer:

A. (\frac{1}{2})² = \frac{1}{2} × \frac{1}{2} = \frac{1}{4}

Step-by-step explanation:

Answer choice (A) is the counterexample because squaring number \frac{1}{2} results into number \frac{1}{4} which is less than \frac{1}{2} .

7 0
3 years ago
Jane needs to memorize words on a vocabulary list for Korean class. She has 18 words to memorize, and she is two-thirds done. Ho
alexgriva [62]
2/3 of 18...." of " means multiply
2/3 * 18 = 36/3 = 12....she has memorized 12 words so far
3 0
3 years ago
Suppose the standard deviation of a normal population is known to be 3, and H0 asserts that the mean is equal to 12. A random sa
blagie [28]

Answer:

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

p_v =P(z>1.9)=0.0287  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=12.95 represent the sample mean

\sigma=3 represent the population standard deviation for the sample  

n=36 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 12, the system of hypothesis would be:  

Null hypothesis:\mu \leq 12  

Alternative hypothesis:\mu > 12  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

P-value  

Since is a right tailed test the p value would be:  

p_v =P(z>1.9)=0.0287  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

4 0
3 years ago
Read 2 more answers
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