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olganol [36]
3 years ago
7

The sum of two integers is 8 their difference is 6 wat are the two integers

Mathematics
1 answer:
pogonyaev3 years ago
3 0

Answer:

7 and 1

Step-by-step explanation:

x+y=8

x-y=6

solve this

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A ratio that compares two quantities measured in different units is a conversion factor!
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Long division of 452.7 ÷ 15<br><br>help me!!​
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30.18

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Evaluate the quantity 3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two.
chubhunter [2.5K]

The value of the expression given as  [3² * 3⁻⁵]/[5⁻²] is 25/27

<h3>How to evaluate the expression?</h3>

The expression is given as:

3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two

Rewrite properly as:

[3² * 3⁻⁵]/[5⁻²]

Apply the negative exponent law of indices

So, we have

[3² * 3⁻⁵]/[5⁻²] = [5²]/[3⁻² * 3⁵]

Apply the exponent law of indices

[3² * 3⁻⁵]/[5⁻²] = [5²]/[3³]

This gives

[3² * 3⁻⁵]/[5⁻²] = 25/27

Hence, the value of the expression given as  [3² * 3⁻⁵]/[5⁻²] is 25/27

Read more about expressions at:

brainly.com/question/723406

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7 0
1 year ago
Can someone please help me? Is the answer 42?
SIZIF [17.4K]

Answer:

X = 46

Step-by-step explanation:

X + 43 + 35 + 56 =180

X + 134 = 180

X = 180 - 134

X = 46

6 0
2 years ago
1. 36(a+b)^2 - 49(a-b(^2
Brums [2.3K]

Answer:

-13a^2 + 170ab - 13b^2.

Step-by-step explanation:

1.  36(a+b)^2 - 49(a-b)^2

This is the difference of 2 squares: a^2 - b^2 = (a + b)(a - b).

36(a+b)^2 - 49(a-b)^2

= (6(a + b) + 7(a - b))(  6(a + b) - 7(a - b))

= (6a  + 7a + 6b - 7b)( 6a - 7a + 6b + 7b)

= (13a - b)(-a + 13b)

If you require the expansion of this it is:

-13a^2 + 170ab - 13b^2.

8 0
3 years ago
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