Jamie takes at random a counter from the bag and records the colour. Red : blue : green = 1:3:7 Jamie does this a number of time
1 answer:
Answer: There are 249 times Jamie takes a counter from the bag.
Explanation:
Since we have given that
Ratio of colour of red to blue to green is 1:3:7.
Number of blue counters = 68
Let the total number of times Jamie does from the bag be x.
So, According to question,
Hence, there are 249 times Jamie takes a counter from the bag.
You might be interested in
The measure of angle ∠EGF is 65°. And the measure of the angle ∠CGE is 115°.
<h3>What is the triangle?</h3>A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.
Triangle GEF is shown with its exterior angles.
Line GF extends through point B.
Line FE extends through point A.
Line EG extends through point C.
Angles ∠FEG and ∠EGF are congruent.
∠FEG = ∠EGF = x
Sides EF and GF are congruent.
Angle ∠EFG is 50° degrees.
∠EFG + ∠FGE + ∠GEF = 180°
50° + x + x = 180°
2x = 130°
x = 65°
∠FEG = ∠EGF = 65°
Then angle ∠CGF will be
∠CGF + ∠FGE = 180°
∠CGF + 65° = 180°
∠CGF = 115°
More about the triangle link is given below.
#SPJ1
Given a complex number in the form:
![z= \rho [\cos \theta + i \sin \theta]](https://tex.z-dn.net/?f=z%3D%20%5Crho%20%5B%5Ccos%20%5Ctheta%20%2B%20i%20%5Csin%20%5Ctheta%5D)
The nth-power of this number,
, can be calculated as follows:
- the modulus of is equal to the nth-power of the modulus of z, while the angle of is equal to n multiplied the angle of z, so:
![z^n = \rho^n [\cos n\theta + i \sin n\theta ]](https://tex.z-dn.net/?f=z%5En%20%3D%20%5Crho%5En%20%5B%5Ccos%20n%5Ctheta%20%2B%20i%20%5Csin%20n%5Ctheta%20%5D)
In our case, n=3, so
is equal to
![z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ]](https://tex.z-dn.net/?f=z%5E3%20%3D%20%5Crho%5E3%20%5B%5Ccos%203%20%5Ctheta%20%2B%20i%20%5Csin%203%20%5Ctheta%20%5D%20%3D%20%285%5E3%29%20%5B%5Ccos%20%283%20%5Ccdot%20330%5E%7B%5Ccirc%7D%29%20%2B%20i%20%5Csin%20%283%20%5Ccdot%20330%5E%7B%5Ccirc%7D%29%20%5D)
(1)
And since
and both sine and cosine are periodic in
, (1) becomes
![z^3 = 125 [\cos 270^{\circ} + i \sin 270^{\circ} ]](https://tex.z-dn.net/?f=z%5E3%20%3D%20125%20%5B%5Ccos%20270%5E%7B%5Ccirc%7D%20%2B%20i%20%5Csin%20270%5E%7B%5Ccirc%7D%20%5D)
The nth-power of this number,
- the modulus of
In our case, n=3, so
And since
and both sine and cosine are periodic in
Maximum value : x=-4
The graph of the parabola opens down, since the value of a (-2) is a negative coefficient. This means the parabola has a maximum value, not a minimum value. The vertex of the parabola is -4, which is the maximum value of the graph.
The graph of the parabola opens down, since the value of a (-2) is a negative coefficient. This means the parabola has a maximum value, not a minimum value. The vertex of the parabola is -4, which is the maximum value of the graph.