2 years ago

The area of triangles and trapezoid

Mathematics

1 answer:

evablogger [386]2 years ago

7 0

Shapes? We need to know how they look like in order to solve

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Solve this so you get coordinates as ur answer

Nostrana [21]

Answer: What topic is this again??

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1 year ago

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Complete the Square and express the quadratic as a square.

Shtirlitz [24]

Answer:

Step-by-step explanation:

x² - 6x + 13 = 0

x² - 2(x)(3) + 3² - 3² + 13 = 0

(x - 3)² = -4

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2 years ago

What is the following product? (5 square root 2-4 square root 3) (5 square root 2-4 square root 3)

Zina [86]

Answer:

(5 square root 2-4 square root 3) (5 square root 2-4 square root 3)

= 98 - 40 $\sqrt{6}$

Step-by-step explanation:

i) (5 $\sqrt{2}$ - 4 $\sqrt{3}$ ) × (5√2 - 4√3)

=(5 $\sqrt{2}$ × 5 $\sqrt{2}$ ) - (5 $\sqrt{2}$ × 4 $\sqrt{3}$ ) - (4 $\sqrt{3}$ × 5 $\sqrt{2}$ ) + (4 $\sqrt{3}$ × 4 $\sqrt{3}$ )

= 50 - 20 $\sqrt{6}$ - 20 $\sqrt{6}$ + 48

= 98 - 40 $\sqrt{6}$

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2 years ago

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If x = 2.5, 5× = _______<br><br>(^u^) please help meh

LenaWriter [7]

x=2.5

5x = 5(2.5) = 12.5

I believe 12.5 is the answer

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3 years ago

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Find the distance between M(-2,3) and N(8,2)

AnnZ [28]

Answer:

$d=\sqrt{101}$

Step-by-step explanation:

Distance Formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Simply plug in your 2 coordinates into the distance formula to find distance <em>d</em>:

$d=\sqrt{(8-(-2))^2+(2-3)^2}$

$d=\sqrt{(8+2)^2+(-1)^2}$

$d=\sqrt{(10)^2+1}$

$d=\sqrt{100+1}$

$d=\sqrt{101}$

6 0

3 years ago