All categories

3 years ago

This question is easy, but the person who answers this gets 100 points! Be fast!

Mathematics

1 answer:

Rzqust [24]3 years ago

6 0

Answer:

B. 400

Step-by-step explanation:

4×4 =16

5^2 = 25

25×1= 25

16×25= 400

You might be interested in

Please help me asap

schepotkina [342]

3.) A *the first one*
4.) C *the last one*

6 0

3 years ago

Read 2 more answers

What is this answer?

zhannawk [14.2K]

I'm NOT 100% confident in my answers.

Graph 1:

Range: Option B

Graph 2:

Range: Option A

The range has to start at zero since that's the lowest point we can go, only one with zero is first option.

RATE AS BRAINLIEST

8 0

3 years ago

How do you solve this In this case 1422 = 5534/(1+r)^4

Sever21 [200]

It is okay to take the inverse of both side given that you remember to exclude the value that make the denominator zero which is in this case r=-1

8 0

3 years ago

What is 3940 times 4869

r-ruslan [8.4K]

Answer:

Step-by-step explanation:

4869 x 3940 = 19183860

4 0

3 years ago

Read 2 more answers

Emergency 911 calls to a small municipality in Idaho come in at the rate of one every two minutes. Assume that the number of 911

nordsb [41]

Answer: a) 30, b) 0.2138, c) 0.0820

Step-by-step explanation:

Since we have given that

X be the number of calls in 1 hour = 60 minutes

Rate of one call every two minutes.

$\lambda=\dfrac{1}{2}$

(a) What is the expected number of 911 calls in one hour?

$\lambda=\dfrac{1}{2}\times 60=30$

(b) What is the probability of three 911 calls in five minutes? If required, round your answer to four decimal places.

$\lambda=\dfrac{1}{2}\times 5=2.5$

Number of calls = 3

So, P(X=3) is given by

$P(X=3)=\dfrac{e^{-\lambda}\lambda^x}{x!}\\\\P(X=3)=\dfrac{e^{-2.5}\times (2.5)^3}{3!}\\\\P(X=3)=0.2138$

(c) What is the probability of no 911 calls during a five-minute period? If required, round your answer to four decimal places.

$P(X=0)=\dfrac{e^{-2.5}(2.5)^0}{0!}=0.0820$

Hence, a) 30, b) 0.2138, c) 0.0820

4 0

4 years ago