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4 years ago

-25(10-x)=5x+50 I don’t understand how to solve this math problem

Mathematics

1 answer:

Tanya [424]4 years ago

3 0

I'm sorry to hear your stuck! Let''s learn how to do this.

Simplify both sides of the equation!

−25(10−x)=5x+50

(−25)(10)+(−25)(−x)=5x+50 - Distribute

−250+25x=5x+50

25x−250=5x+50

Now subtract 5x to each side.

25x−250−5x=5x+50−5x

20x−250=50

Add 250 to both sides. (We need to get x by itself)

20x−250+250=50+250

20x=300

Divide both sides by 20!

You get x = 15.

I'd take notes and look through on how this problem was solved for future references.

Have a good one!

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The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

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Statement is incorrect. Correct form is presented below:

The height $h(t)$ of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation $h(t) = 3 +90\cdot t -16\cdot t^{2}$ , where $t$ is time in seconds. After how many seconds will the ball be 84 feet above the ground.

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

$3+90\cdot t -16\cdot t^{2} = 84$

$16\cdot t^{2}-90\cdot t +81 = 0$ (1)

By Quadratic Formula:

$t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}$

$t_{1} = 4.5\,s$ , $t_{2} = 1.125\,s$

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