<u>Answer:</u>
The baseball cards remain in Nathan’s collection is 106 cards
<u>Explanation:</u>
Total number of cards Nathan has= 220
Number of cards he let his brother have = 1/4 of his collection
=
= 55 cards
Number of cards he sells = 20% of his collection
=
=44 cards
No of cards he gives to his friends=15 cards
Remaining cards = total number of cards – (no of cards he gave to his brother+ cards he sold+ cards he gave to this friends)
= 220 – ( 55+44+15)
=220-114
=106 cards
baseball cards remain in Nathan’s collection is 106 cards
$1.87 is the answer
explanation: divide $7.48 and 4 because it says per each marker and a little trick: each = divide or multiply! good luck with your school <3
Answer:
Step-by-step explanation:
Let the speed of plane is p and speed of the wind is w.
<u>Then we have:</u>
- 10*(p + w) = 1120 ⇒ p + w = 112
- 20*(p - w) = 1120 ⇒ p - w = 56
<u>Sum the two equations and solve for p:</u>
- p + w + p - w = 112 + 56
- 2p = 168
- p = 84
<u>Find w:</u>
- 84 + w = 112
- w = 112 - 84
- w = 28
Answer: where is the question??
First of all, you have to understand
<span> is a square-root function.
</span>Square-root functions are continuous across their entire domain, and their domain is all real x-<span>values for which the expression within the square-root is non-negative.
</span>
In other words, for any square-root function
and any input
in the domain of
(except for its endpoint), we know that this equality holds:
Let's take
<span>as an example.
</span>
The domain of
is all real numbers such that
. Since
is the endpoint of the domain, the two-sided limit at that point doesn't exist (you can't approach
<span>from the left).
</span>
<span>However, continuity at an endpoint only demands that the one-sided limit is equal to the function's value:
</span>
In conclusion, the equality
holds for any square-root function
and any real number
in the domain of
e<span>xcept for its endpoint, where the two-sided limit should be replaced with a one-sided limit. </span>
The input
, is within the domain of
<span>.
</span>
Therefore, in order to find
we can simply evaluate
at
<span>.
</span>
