Answer:
1. When a cold air mass and a warm air mass meet but are at a standstill, the boundary is called stationary front.
2. If warm or more humid air presses forward and colder or drier air draws back, the boundary is called warm front.
3. If colder or drier air presses forward and warmer or more humid air draws back, the boundary is called cold front.
4. Sometimes a warm air mass can get caught between two cold fronts, which can force the warm air up into a wedge shape is called occluded front.
In an atom of hydrogen the orbit radius is given by the formula:
r = n² · α₀
where:
n = number of orbit = 15
α₀ = Bohr radius (innermost radius) = 0.529 Â
Since d = 2 · r, we can write:
d = n² · d₀
= 15² · 1.06
= 238.5 Â
Hence, the <span>diameter of the fifteenth orbit of the hydrogen atom is 238.5 </span>Â.
Answer:
No she cannot.
Explanation:
Let 
be the horizontal component of the ball velocity when it's kicked, assume no air resistance, this is a constant. Also let 
be the vertical component of the ball velocity, which is affected by gravity after it's kicked.
The time it takes to travel 95m accross the field is
or 
t is also the time it takes to travel up, and the fall down to the ground, which ultimately stops the motion. So the vertical displacement after time t is 0
where g = -9.8m/s2 in the opposite direction with
Since the total velocity that the goal keeper can give the ball is 30m/s
Let substitute x = 
> 0
We can multiply both sides by x
As 
The solution for this quadratic equation is indefinite
So it's not possible for the goal keeper to do this.
<span>I found out F2 and its correct just need help in solving the other parts </span>
<span>F2 = 4.5 N </span>
Electronic signals are converted into a 'ray of light' -
