Answer:
Explanation:
Given
mass of bus along with travelers travelling in North direction is ![m_1=1.6\times 10^4 kg](https://tex.z-dn.net/?f=m_1%3D1.6%5Ctimes%2010%5E4%20kg)
speed of bus towards North ![v_1=15.2 km/h\approx 4.22\ m/s](https://tex.z-dn.net/?f=v_1%3D15.2%20km%2Fh%5Capprox%204.22%5C%20m%2Fs)
mass of bus travelling in South direction is ![m_2=1.578\times 10^4 kg](https://tex.z-dn.net/?f=m_2%3D1.578%5Ctimes%2010%5E4%20kg)
speed of bus ![v_2=12.2 km/h\approx 3.38\ m/s](https://tex.z-dn.net/?f=v_2%3D12.2%20km%2Fh%5Capprox%203.38%5C%20m%2Fs)
mass of each Passenger in south moving bus ![m_0=64.8 kg](https://tex.z-dn.net/?f=m_0%3D64.8%20kg)
Momentum of North moving bus
![P_1=m_1\times v_1](https://tex.z-dn.net/?f=P_1%3Dm_1%5Ctimes%20v_1)
![P_1=1.6\times 10^4\times 4.22](https://tex.z-dn.net/?f=P_1%3D1.6%5Ctimes%2010%5E4%5Ctimes%204.22)
![P_1=6.768\times 10^4 kg-m/s](https://tex.z-dn.net/?f=P_1%3D6.768%5Ctimes%2010%5E4%20kg-m%2Fs)
Momentum with south moving bus
![P_2=m_2\times v_2+n\cdot m_0\times v_2](https://tex.z-dn.net/?f=P_2%3Dm_2%5Ctimes%20v_2%2Bn%5Ccdot%20m_0%5Ctimes%20v_2)
![P_2=(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38](https://tex.z-dn.net/?f=P_2%3D%281.578%5Ctimes%2010%5E4%2Bn%5Ccdot%2064.8%20%29%5Ccdot%203.38)
For total momentum to be towards south
should be greater than 0
thus for least value of n
![P_2=P_1](https://tex.z-dn.net/?f=P_2%3DP_1)
![(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38=6.768\times 10^4](https://tex.z-dn.net/?f=%281.578%5Ctimes%2010%5E4%2Bn%5Ccdot%2064.8%20%29%5Ccdot%203.38%3D6.768%5Ctimes%2010%5E4)
![1.578\times 10^4+n\cdot 64.8=2.0023\times 10^4](https://tex.z-dn.net/?f=1.578%5Ctimes%2010%5E4%2Bn%5Ccdot%2064.8%3D2.0023%5Ctimes%2010%5E4)
Answer:![81.57\mu V](https://tex.z-dn.net/?f=81.57%5Cmu%20V)
Explanation:
Given
radius of circular region r=1.50 mm
![A=\pi r^2=7.069\times 10^{-6}\ m^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%3D7.069%5Ctimes%2010%5E%7B-6%7D%5C%20m%5E2)
Magnetic Field ![B=1.50\ T](https://tex.z-dn.net/?f=B%3D1.50%5C%20T)
time t=130 ms
Flux is given by
![\phi =B\cdot A](https://tex.z-dn.net/?f=%5Cphi%20%3DB%5Ccdot%20A)
change in Flux ![d\phi =(B_f-B_i)A](https://tex.z-dn.net/?f=d%5Cphi%20%3D%28B_f-B_i%29A)
Emf induced is ![e=\frac{\mathrm{d} \phi}{\mathrm{d} t}](https://tex.z-dn.net/?f=e%3D%5Cfrac%7B%5Cmathrm%7Bd%7D%20%5Cphi%7D%7B%5Cmathrm%7Bd%7D%20t%7D)
![e=\frac{(1.5)\cdot 7.069\times 10^{-6}}{130\times 10^{-3}}](https://tex.z-dn.net/?f=e%3D%5Cfrac%7B%281.5%29%5Ccdot%207.069%5Ctimes%2010%5E%7B-6%7D%7D%7B130%5Ctimes%2010%5E%7B-3%7D%7D)
![e=81.57 \mu V](https://tex.z-dn.net/?f=e%3D81.57%20%5Cmu%20V)
Protons and neutrons are located in the nucleus, a dense central core in the middle of the atom, while the electrons are located outside the nucleus.
Answer:
Force(Romeo moving) = 5,000 N
Explanation:
Given:
Mass of horse = 900 kg
Acceleration = 20 km/hr
Find:
Force(Romeo moving)
Computation:
Acceleration = 20 km/hr
Acceleration in m/s = 20 / 3.6 = 5.555556 m/s²
Force = m x a
Force(Romeo moving) = 900 x 5.555556
Force(Romeo moving) = 5,000 N