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Vesna [10]
3 years ago
8

Dan and Chris share in the profits of a toy store. If the total profit is ​$80,000 and c is the amount Chris ​receives, write an

expression for the amount Dan receives.
Mathematics
1 answer:
Naily [24]3 years ago
4 0

Answer:

d = 80,000 - c

Step-by-step explanation:

Amount Dan receives = d

The total profit of what Dan receives plus what Chris receives is 80,000, so we can write:

d + c = 80,000

To solve that as an expression of what Dan receives, we can subtract both sides by c

d = 80,000 - c

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One eighth of the class graduated with an A average, 1/2 got a B, and the rest of the class had a C average. In a class of 800,
pogonyaev
I believe the answer would be 300. One eighth of the class would be 100 and 1/2 of the class would be 400. 800-(400+100)=300. Hope this helped!
8 0
3 years ago
Read 2 more answers
PLEASE HELP!!! DUE IN 10 MIN!!!
9966 [12]

Answer:

Option B

Step-by-step explanation:

Surface area of a triangular prism = Area of the triangular sides + Area of the rectangular sides

Area of the triangular sides = 2(Area of the triangular base)

                                              = 2[\frac{1}{2}(\text{Base})(\text{Height})]

                                              = 10 × 12

                                              = 120 ft²

Area of the rectangular sides = (Perimeter of the triangular side)(Height of the prism)    

= (10 + 13 + 13)(15)

= 36 × 15

= 540 ft²

Surface area of the prism = 120 + 540

                                           = 660 square feet

Option B will be the answer.

5 0
2 years ago
Which two tables represent the same function?
topjm [15]

Answer:

The 1st and the 5th tables represent the same function

Step-by-step explanation:

* Lets explain how to solve the problem

- There are five tables of functions, two of them are equal

- To find the two equal function lets find their equations

- The form of the equation of a line whose endpoints are (x1 , y1) and

  (x2 , y2) is \frac{y-y_{1}}{x-x_{1}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

* Lets make the equation of each table

# (x1 , y1) = (4 , 8) and (x2 , y2) = (6 , 7)

∵ x1 = 4 , x2 = 6 and y1 = 8 , y2 = 7

∴ \frac{y-8}{x-4}=\frac{7-8}{6-4}

∴ \frac{y-8}{x-4}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 8) = -1(x - 4) ⇒ simplify

∴ 2y - 16 = -x + 4 ⇒ add x and 16 for two sides

∴ x + 2y = 20 ⇒ (1)

# (x1 , y1) = (4 , 5) and (x2 , y2) = (6 , 4)

∵ x1 = 4 , x2 = 6 and y1 = 5 , y2 = 4

∴ \frac{y-5}{x-4}=\frac{4-5}{6-4}

∴ \frac{y-5}{x-4}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 5) = -1(x - 4) ⇒ simplify

∴ 2y - 10 = -x + 4 ⇒ add x and 10 for two sides

∴ x + 2y = 14 ⇒ (2)

# (x1 , y1) = (2 , 8) and (x2 , y2) = (8 , 5)

∵ x1 = 2 , x2 = 8 and y1 = 8 , y2 = 5

∴ \frac{y-8}{x-2}=\frac{5-8}{8-2}

∴ \frac{y-8}{x-2}=\frac{-3}{6}=====\frac{y-8}{x-2}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 8) = -1(x - 2) ⇒ simplify

∴ 2y - 16 = -x + 2 ⇒ add x and 16 for two sides

∴ x + 2y = 18 ⇒ (3)

# (x1 , y1) = (2 , 10) and (x2 , y2) = (6 , 14)

∵ x1 = 2 , x2 = 6 and y1 = 10 , y2 = 14

∴ \frac{y-10}{x-2}=\frac{14-10}{6-2}

∴ \frac{y-10}{x-2}=\frac{4}{4}======\frac{y-10}{x-2}=1

- By using cross multiplication

∴ (y - 10) = (x - 2)

∴ y - 10 = x - 2 ⇒ add 2 and subtract y in the two sides

∴ -8 = x - y ⇒ switch the two sides

∴ x - y = -8 ⇒ (4)

# (x1 , y1) = (2 , 9) and (x2 , y2) = (8 , 6)

∵ x1 = 2 , x2 = 8 and y1 = 9 , y2 = 6

∴ \frac{y-9}{x-2}=\frac{6-9}{8-2}

∴ \frac{y-9}{x-2}=\frac{-3}{6}======\frac{y-9}{x-2}=\frac{-1}{2}

- By using cross multiplication

∴ 2(y - 9) = -1(x - 2) ⇒ simplify

∴ 2y - 18 = -x + 2 ⇒ add x and 18 for two sides

∴ x + 2y = 20 ⇒ (5)

- Equations (1) and (5) are the same

∴ The 1st and the 5th tables represent the same function

3 0
3 years ago
Can someone walk me through this?
Diano4ka-milaya [45]
So you can set up proportion.

\dfrac{7.5\ \text m}{76^\circ} = \dfrac C{360^\circ}

Here, you need to solve for C.

You can do that by multiple both sides by 360 and then you should get 360^\circ\cdot\dfrac{7.5\ \text m}{76^\circ} = C \approx \boxed{35.526\ \text m}

Hope this helps.
3 0
3 years ago
Pls Answer really need it
vfiekz [6]
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