Answer:
The height of the prism is ![24\ in](https://tex.z-dn.net/?f=24%5C%20in)
Step-by-step explanation:
we know that
The volume of the rectangular prism is equal to
![V=LWH](https://tex.z-dn.net/?f=V%3DLWH)
In this problem we have
![V=5,376\ in^{3}](https://tex.z-dn.net/?f=V%3D5%2C376%5C%20in%5E%7B3%7D)
![L=14\ in](https://tex.z-dn.net/?f=L%3D14%5C%20in)
![W=16\ in](https://tex.z-dn.net/?f=W%3D16%5C%20in)
substitute in the formula and solve for H
![5,376=(14)(16)H](https://tex.z-dn.net/?f=5%2C376%3D%2814%29%2816%29H)
![H=5,376/[(14)(16)]](https://tex.z-dn.net/?f=H%3D5%2C376%2F%5B%2814%29%2816%29%5D)
![H=24\ in](https://tex.z-dn.net/?f=H%3D24%5C%20in)
Answer:
−33999/50
Step-by-step explanation:
2/100−680
=
1/50−680
=
−33999/50
Answer:
3x/16+1/4
Step-by-step explanation:
Answer:
Distance formula is below
Step-by-step explanation:
The answer is C.
To solve these types of equations you first need to make sure that you equation is equal to 0. In this case all of the numbers are already on the same side so no work needs to be done there. Then we can get a, b and c values for the quadratic equation by looking at the coefficients.
a = 4 (number attached to x^2)
b = -6 (number attached to x)
c = 1 (number with no variable attached)
Now we can put this into the quadratic equation.
![\frac{-b +/- \sqrt{ b^{2} -4ac} }{2a}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-b%20%2B%2F-%20%20%5Csqrt%7B%20b%5E%7B2%7D%20-4ac%7D%20%7D%7B2a%7D%20)
![\frac{6 +/- \sqrt{ -6^{2} -4(4)(1)} }{2(4)}](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%20%2B%2F-%20%5Csqrt%7B%20-6%5E%7B2%7D%20-4%284%29%281%29%7D%20%7D%7B2%284%29%7D%20)