this question is incomplete, the complete question is:
1. is this model effective
2. what is the correlation coefficient for this data.
3. for a student with a bmi of 25, what is the predicted number of hours under the influence.
Step-by-step explanation:
1. first of all this model is not effective because we have r² as 0.134. this tells us that only 13.4 percent of the of the variations that exist in this data has been explained by the model
1. we get the correlation coefficient by
the regression slope coefficient has a negative sign. this is what we would use in calculating the correlation coefficient.
= -√0.134
= -0.366
therefore the correlation coefficient is -0.366
2. to get the number of hours under the influence with a bmi of 25
the equation is
49.2-1.15bmi
= 49.2-1.15(25)
= 49.2-28.75
= 20.45
Answer:
Claim : men weigh of wild jackalopes is 69.9
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Test statistic = −2.447085
P value = 0.0174
Conclusion :
Fail to Reject the Null hypothesis
Step-by-step explanation:
From the question given :
The claim is that : mean weight of wild jackalopes is still the same as 10 years with a mean weight of 69.9 lbs.
The null hypothesis : H0 : μ = 69.9
Alternative hypothesis : H1 : μ ≠ 69.9
Using calculator :
Sample mean (x) = 66
Sample standard deviation (s) = 12.345
The test statistic t :
(x - μ) / (s/√n)
n = sample size = 60
(66 - 69.9) / (12.345 / √60)
t = −2.447085
P value at α 0.01, df = 59 is 0.0174
Since the p value is > 0.01, the result is not significant at 0.01. Therefore, we fail to reject the Null
Answer:
g(x) = log( x + 1 ) + 4
Step-by-step explanation:
f(x) is the parent equation so to get g(x) we shifted f(x) four units up and one unit to the left.
His mean score for the first 4 games will be 18 points.
Explanation
In the first 3 games, the mean of the scores is 15 points . Mean is the simple average of some numbers.
So, the total score in first 3 games = 
points
Now, in the 4th game, he scored 27 points. So, the total score in the first 4 games = 
points
Thus, the average of scores in first 4 games = 
points
So, his mean score for the first 4 games will be 18 points.
The slope is -2 and the Y-Intercept is at 24
