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Natalka [10]
3 years ago
7

A well respected wild life researcher recently conducted a

Mathematics
1 answer:
Marina CMI [18]3 years ago
7 0

Answer:

Claim : men weigh of wild jackalopes is 69.9

The null hypothesis : H0 : μ = 69.9

Alternative hypothesis : H1 : μ ≠ 69.9

Test statistic = −2.447085

P value = 0.0174

Conclusion :

Fail to Reject the Null hypothesis

Step-by-step explanation:

From the question given :

The claim is that : mean weight of wild jackalopes is still the same as 10 years with a mean weight of 69.9 lbs.

The null hypothesis : H0 : μ = 69.9

Alternative hypothesis : H1 : μ ≠ 69.9

Using calculator :

Sample mean (x) = 66

Sample standard deviation (s) = 12.345

The test statistic t :

(x - μ) / (s/√n)

n = sample size = 60

(66 - 69.9) / (12.345 / √60)

t = −2.447085

P value at α 0.01, df = 59 is 0.0174

Since the p value is > 0.01, the result is not significant at 0.01. Therefore, we fail to reject the Null

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