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insens350 [35]
3 years ago
15

What times what equals 50

Mathematics
2 answers:
klasskru [66]3 years ago
8 0
Twenty-five times two = fifty
yan [13]3 years ago
8 0
5 times 10 equals 50
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Write the missing exponent<br> 8=2
Mila [183]

Answer:

2^3 =8

Step-by-step explanation:

2*2 =4

4*2 =8

2*2*2 =8

2^3 =8



8 0
3 years ago
Read 2 more answers
If RT = 6 and RS = 9, then RX =<br> A - sqrt(54)<br> B - 13.5<br> C - 7.2<br> D - 4
wolverine [178]

Answer:

Option D RX=4 units

Step-by-step explanation:

we know that

<em>In the right triangle RTS</em>

The cosine of angle TRS is equal to

cos(TRS)=RT/RS

substitute

cos(TRS)=6/9 -----> equation A

<em>In the right triangle RTX</em>

The cosine of angle TRX is equal to

cos(TRX)=RX/RT

substitute

cos(TRX)=RX/6 -----> equation B

∠TRS=∠TRX -----> is the same angle

Match equation A and equation B

6/9=RX/6

RX=6*6/9=4 units

5 0
3 years ago
Can yall help me out
Ainat [17]

Answer:

Option D, Yes, Devon should have evaluated f(3)

Step-by-step explanation:

f(x) = x^3 + x^2 − 10x + 8

<u>Step 1:  Evaluate using F(3) NOT f(-3)</u>

f(3) = 3^3 + 3^2 - 10(3) + 8

f(3) = 27 + 9 - 30 + 8

f(3) = 14

Since the factor is (x - 3) the x value is x - 3 + 3 = 0 + 3 -> x = 3 not x = -3

Answer:  Option D, Yes, Devon should have evaluated f(3)

6 0
3 years ago
A marine aquarium has a small tank and a large tank, each containing only red and blue fish. In each tank, the ratio of red fish
Anna007 [38]

Answer:

Ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

Step-by-step explanation:

Let the number of red fish and blue fish in the large tank are x and y respectively.

Similarly ratio of red fish and blue fish in the small tank are x' and y' respectively.

Since in each tank ratio of the red fish to blue fish is 333 : 444

That means x : y = 333 : 444

Or \frac{x}{y}=\frac{333}{444}

⇒ \frac{x}{y}=\frac{3}{4}

⇒ y = \frac{4x}{3} --------(1)

Similarly x' : y' = 333 : 444

⇒ \frac{x'}{y'}=\frac{333}{444}

⇒ \frac{x'}{y'}=\frac{3}{4}

⇒ x' = \frac{3y'}{4} ------(2)

Ratio of the fish in large tank to the fish in small tank is 464646 : 555

So (x + y) : (x' + y') = 464646 : 555

\frac{x+y}{x'+y'}=\frac{464646}{555}

Now we replace the values of x and y' from equation (1) and equation (2)

\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}

\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}

\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}

\frac{x}{y'}=\frac{3}{4}\times \frac{464646}{555}

\frac{x}{y'}=\frac{232323}{370}

\frac{y'}{x}=\frac{370}{232323}

\frac{y'}{x}=\frac{10}{6279}

Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

4 0
3 years ago
An older car weighs 2 tons. A newer model of the car weighs 40 pounds more than the previous model. How much does the newer mode
ExtremeBDS [4]
1 ton. = 2000 pounds
2 tons. = 4000 pounds _old model
4000+40=4,040 pounds_newer model

8 0
3 years ago
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