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3 years ago

What is the slope of the line through the points (0,0) and (2,6)

Mathematics

1 answer:

Aneli [31]3 years ago

8 0

Answer:

Step-by-step explanation:

The slope of a line can be found by dividing the amount that the line "rises" over a certain amount of "run". In this case, the line rises 6 units while moving 2 units to the right. 6/2=3, meaning that the slope of this line is 3. Hope this helps!

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Pls help i dont know how to do this

Vlad [161]

2/5 and then when you graph it’s rise 2 and over 5

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3 years ago

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At a football stadium, 10% of the fans in attendance were teenagers. If there were 330

pishuonlain [190]

Answer: 3300 teenagers

Step-by-step explanation:

10/100

330/x

After you cross multiply then divide, x equals 3300.

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3 years ago

3/6 times 2/6. Please show step by step directions I NEED HELP ASAP

viva [34]

To solve, simply layout and equation.

3/6*2/6.

Step 1: Simply 3/6.

1/2*2/6

Step 2: Simplify 2/6.

1/2*1/3

Step 3: Multiply.

1/2*1/3

1/6.

So, the answer to this problem is 1/6.

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3 years ago

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Solve -2x-8>3x+12 (Picture added, multiple choice)

QveST [7]

It will be c i showed how on paper

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3 years ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

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3 years ago

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