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3 years ago

Kate is 142 cm tall. this is 2 cm less than 3 times her height at birth whst is her height at birth

Mathematics

1 answer:

kramer3 years ago

4 0

Welcome to Brainly!

Let h represent Kate's height at birth. Then: 142 cm = 3h - 2 cm.

Combining like terms: 144 cm = 3h, and h = 48 cm.

Kate's height at birth was 48 cm.

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Combine Radicals/Fractional Exponents

Crazy boy [7]

$\mathsf{Given :\;\;\dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{\sqrt[3]{64x^3y^3}}}$

$\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{\sqrt[3]{4^3x^3y^3}}}$

$\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{\sqrt[3]{(4xy)^3}}}$

$\bigstar\;\;\textsf{We know that : \boxed{\mathsf{\sqrt[n]{a} = a^{\dfrac{1}{n}}}}}$

$\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{{(4xy)^{\dfrac{3}{3}}}}}$

$\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{{4xy}}}$

$\mathsf{\implies \left(\dfrac{5}{4}\right) \left(\dfrac{x^{\dfrac{-3}{2}}}{{x}}\right)\left(\dfrac{y^{-2}}{y}\right)}$

$\bigstar\;\;\textsf{We know that : \boxed{\dfrac{a^m}{a^n} = a^{m - n}}}}$

$\mathsf{\implies \left(\dfrac{5}{4}\right) x^{\left(\dfrac{-3}{2} - 1\right)}}y^{(-2 - 1)}}$

$\mathsf{\implies \left(\dfrac{5}{4}\right) x^{\left(\dfrac{-3 - 2}{2}\right)}}y^{-3}}$

$\mathsf{\implies \left(\dfrac{5}{4}\right) x^{\left(\dfrac{-5}{2}\right)}}y^{-3}}$

$\textsf{Comparing the above with $\mathbf{ax^by^c}$, We can notice that :}$

$\bigstar\;\;\mathsf{a = \dfrac{5}{4}}$

$\bigstar\;\;\mathsf{b = \dfrac{-5}{2}}$

$\bigstar\;\;\mathsf{c = -3}$

$\implies \mathsf{Product\;of\;a,\;b\;and\;c = \left(\dfrac{5}{4}\times \dfrac{-5}{2} \times -3\right)}$

$\implies \mathsf{Product\;of\;a,\;b\;and\;c = \dfrac{75}{8}}$

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3 years ago

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sineoko [7]

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3 years ago

Read 2 more answers

What is 2^5+6? Show how you got it.

Westkost [7]

Answer:

Step-by-step explanation:

Raise 2 to the power of 5 .

32+6

Add 32 and 6 .

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4 0

3 years ago

Show your work for the right answer

Degger [83]

Answer:

= a^7

Step-by-step explanation:

Given in the question,

a^5 * a^4 / a²

To find,

show working

<h3>Explanation</h3>

As we know that to divide exponents (or powers) with the same base, we subtract the exponents. Division is the opposite of multiplication, so when multiplying the exponents (or powers) with the same base add the exponents.

<h3>Working</h3>

a^5 * a^4 / a²

= a^(5 + 4) / a² (Multiplying)

= a^9 / a²

= a^(9 - 2) (Dividing)

= a^7

<em>hence shown</em>

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hram777 [196]

2.......................

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