Answer:
Step-by-step explanation:
Given coordinates are (6,-3) and (-5,-4).
![\sf Slope = \frac{y2-y1}{x2-x1}\\\\Slope = \frac{-4+3}{-5-6} \\\\Slope = \frac{-1}{-11} \\\\Slope = \frac{1}{11} \\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20Slope%20%3D%20%5Cfrac%7By2-y1%7D%7Bx2-x1%7D%5C%5C%5C%5CSlope%20%3D%20%5Cfrac%7B-4%2B3%7D%7B-5-6%7D%20%5C%5C%5C%5CSlope%20%3D%20%5Cfrac%7B-1%7D%7B-11%7D%20%5C%5C%5C%5CSlope%20%3D%20%5Cfrac%7B1%7D%7B11%7D%20%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AnonymousHelper1807</h3>
The sum of the angles should be 180, so x+ (x+10) + (x+5) = 180. This simplifies to 3x + 15 = 180, so 3x = 165, so x=55.
Answer:
5
Step-by-step explanation:
So we want to find the value of x where the area to the left of it is equal to 0.6.
Let's start by finding the area of the first triangle, between x=0 and x=4.
A = 1/2 bh
A = 1/2 (4) (0.2)
A = 0.4
So we know a > 4. What if we add the area of that rectangle?
A = 0.4 + bh
A = 0.4 + (1) (0.2)
A = 0.6
Aha! So a = 5.
The first one is infinite many solutions
The second one is (x=0) one solution
The third one is (x=3) one solution
The fourth one is no solution
The last one is no solution
