Answer:
A
Step-by-step explanation:
We are given a parabola with a vertex point of (2, 1) and a <em>y-</em>intercept of <em>y</em> = 4.
And we want to determine another point on the parabola.
Recall that a parabola is symmetric along the axis of symmetry, which is the <em>x-</em>coordinate of the vertex.
Note that since the <em>y-</em>intercept of the parabola is <em>y</em> = 4, this means that a point on our parabola is (0, 4).
To get from (2, 1) to (0, 4), we move two units left and three units up.
Since the parabola is symmetric along axis of symmetry, another point on the parabola will be two units right and three units up. This yields (2 + 2, 1 + 3) or (4, 4).
Our answer is A.
Xy = 6
x + y = 9
x + y = 9
x - x + y = -x + 9
y = -x + 9
xy = 6
x(-x + 9) = 6
x(-x) + x(9) = 6
-x² + 9x = 6
-x² + 9x - 6 = 0
-1(x²) - 1(-9x) - 1(6) = 0
-1(x² - 9x + 6) = 0
-1 -1
x² - 9x + 6 = 0
x = -(-9) ± √((-9)² - 4(1)(6))
2(1)
x = 9 ± √(81 - 24)
2
x = 9 ± √(57)
2
x = 4.5 ± 0.5√(57)
x + y = 9
4.5 ± 0.5√(57) + y = 9
- (4.5 ± 0.5√(57)) - (4.5 ± 0.5√(57))
y = 4.5 ± 0.5√(57)
(x, y) = (4.5 ± 0.5√(57), 4.5 ± 0.5√(57))
The two numbers that multiply to 6 and add up to 9 are 4.5 ± 0.5√(57).
You forgot to add a picture
The smallest value is $0.25 (a quarter) because you can use two quarters and a half dollar. Only one of them can't be a half dollar, but the other two can be.
