1 mol 2 mol
84g of N2(g) = 84/28 = 3 mol of N2(g)
From the above reaction 1 mol of N2(g) gives 2 mol 0f NH3(g). So 3 mol of N2(g) should give 6 mol or (6x17) 102 g of NH3(g). But we are getting only 85.0 g of NH3.
Hence %yield of NH3 = 100x85.0/102 = 83.3%
Answer D. is correct.
2. 2HgO (s) --------------------- 2Hg (l) + O2 (g)
2 mol 2 mol 1 mol
4 mol 4 mol 2 mol
As only 1.5 mol of O2 is obtained, so % yield = 1.5x100/2 = 75.0%
Moreover 603 g of Hg = 603/200.59 = 3.00 molof Hg. Considering this also
% yield = 3x100/4 = 75%
If water were flowing from area A to area B via osmosis, through a semipermeable membrane, we might expect are B to be high in solute concentration compared to A. Osmosis is the process by which water moves from a region of a high concentration to a region of low concentration through a semipermeable membrane. It means area A is hypotonic (more water molecules than solute molecules) while area B is hypertonic (more solute molecules than water molecules).
I think you forgot to attach the statements along with the question. I am answering the question based on my knowledge and research. "It's evolution within a single population" is the one statement that <span>is true about microevolution. I hope that this is the answer that has come to your great help.</span>
Carbs-Monosaccharide, Lipid-Triglycerides, Protein-Amino Acids, Nucleic Acids-Nucleotides!