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3 years ago

Given that 2^x=7 then what is 4^x-1

Mathematics

2 answers:

Dimas [21]3 years ago

7 0

It depend what you mean

First 4∧x -1 = (2∧2)∧x -1 = (2∧x)∧2 -1 = 7∧2 -1 = 49-1 = 48

Second 4∧(x-1)= (2∧2)∧(x-1)=2∧(2x-2)=(2∧x)∧2/4=7∧2/4=49/4

Sergeu [11.5K]3 years ago

4 0

4^x=2×2^x=2×7=14
4^x-1=14-1=13

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2 years ago

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2) Evaluate the given numerical expression. A) 9 B) 12 C) 14 D) 21

eduard

Answer:

$\boxed{\sf{14}}$

Step-by-step explanation:

$\boxed{\underline{\text{ORDER OF OPERATIONS:}}}$

Use the order of operations.

Note: PEMDAS or BODMAS stands for:

PEMDAS

Parentheses
Exponents
Multiply
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BODMAS

Brackets
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First, do parentheses.

3+6*(5+4)÷3-7

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$\Longrightarrow: \sf{3+6* 9\div 3-7}$

Do multiply and divide.

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Then, rewrite the problem down.

$\Longrightarrow: \sf{3+18-7}$

Add.

$\sf{3+18=21}$

$\sf{21-7=\boxed{\sf{14}}$

$\Longrightarrow: \boxed{\sf{14}}$

Therefore, the correct answer is "C. 14".

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3 years ago

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31.064=>31.06=>31.1

I hope this helps uuu!

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