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Likurg_2 [28]
3 years ago
11

Given that 2^x=7 then what is 4^x-1

Mathematics
2 answers:
Dimas [21]3 years ago
7 0

It depend what you mean

First    4∧x -1 = (2∧2)∧x -1 = (2∧x)∧2 -1 = 7∧2 -1 = 49-1 = 48

Second  4∧(x-1)= (2∧2)∧(x-1)=2∧(2x-2)=(2∧x)∧2/4=7∧2/4=49/4

Sergeu [11.5K]3 years ago
4 0
4^x=2×2^x=2×7=14
4^x-1=14-1=13
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Evaluate 2x2+y23 for x = 1.5 and y = 3. Show all of your work.
Lera25 [3.4K]

Answer:

73.5

Step-by-step explanation:

I assume you are trying to find 4x+23y. To do this, let's plug in 1.5 for x and 3 for y. When we do so, we get 4*1.5 + 23*3 = 6 + 69 = 75. Hope this helps!

6 0
3 years ago
A concert sold general admission tickets for $47.50 and lower-level seating for $97.50. The 995 tickets sold took in $68,762.50.
BabaBlast [244]

Answer: 565 general admission and 430 lower-level seating tickets sold (Answer (D))

Steps:

Let x be the number of general admission tickets, and y be the number of lower level tickets.

Set up the two equations:

68762.5 = x * 47.50 + y * 97.50       (total price as a sum of individual volumes)

x + y = 995    (sum of individual count = total count of tickets sold)

solve for x, y:

x = 995 - y

plug into the first equation:

68762.5 = (995-y) * 47.50 + y * 97.50

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x = 565 and y = 430


8 0
3 years ago
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What multiplication problem equals 160
rodikova [14]
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Leokris [45]

Answer:

The sum of the first 47 terms of the series, 12, 16, 20, ... S₄₈ is 4,888

Step-by-step explanation:

The given series is;

12, 16, 20, ...,

Therefore, the first term of the series is, a = 12

The common difference of series is found as follows;

The difference between subsequent terms, 12 and 16 is  16 - 12 = 4

The difference between subsequent terms, 16, and 20 is  20 - 16 = 4

Therefore, the common difference, d = 4

The series is therefore an arithmetic projection, AP

The sum of the first 'n' terms of an AP, Sₙ, is given as follows;

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(47/2)*(2*12+(47-1)*4)

The sum of the first 47 terms is therefore given as follows;

S_n = \dfrac{47}{2} \cdot \left [2 \times 12 + (47 - 1)\times 4 \right ] = 4,888

The sum of the first 47 terms of the series, 12, 16, 20, ... S₄₈ = 4,888

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