A parallelogram has a base of length 2x + 1 and a height of x + 3 and has an area of
2 answers:
Answer:
Step-by-step explanation:
Using the given expressions, we can write the area as ...
A = BH
42 = (2x +1)(x +3) = 2x^2 +7x +3
2x ^2 +7x -39 = 0
(x -3)(2x +13) = 0
x = 3 or -6.5 . . . . . these values make the factors be zero
In order for the parallelogram to have positive dimensions, the value of x must be 3. So, the base and height are ...
base = 2(3) +1 = 7
height = 3 +3 = 6
Answer: height = 6 units
Base = 7 units
Step-by-step explanation:
The formula for determining the area of a parallelogram is expressed as
Area = BH
B = 2x + 1
H = x + 3
If area = 42 square units, then
(2x + 1)(x + 3) = 42
2x² + 6x + x + 3 = 42
2x² + 7x + 3 - 42 = 0
2x² + 7x - 39 = 0
2x² + 13x - 6x - 39 = 0
x(2x + 13) - 3(2x + 13) = 0
x - 3 = 0 or 2x + 13 = 0
x = 3 or x = - 13/2 = - 6.5
Since x cannot be negative, then x = 3
Therefore,
Base = 2x + 1 = 2 × 3 + 1 = 7 units
Height = x + 3 = 3 + 3 = 6 units
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