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4 years ago

How many pounds are in 34 ounces

Mathematics

2 answers:

Morgarella [4.7K]4 years ago

8 0

There is 2.125 pounds in 34 ounces

Tju [1.3M]4 years ago

4 0

Answer:

2.125

Step-by-step explanation:

divide the mass value by 16

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What is the period, in seconds, of a simple pendulum of length 2 meters? Use the gravitational constant g = 9.8 m/s^2 and round

kirill [66]

Answer:

The period, in seconds to two decimal places is, 2.84 sec

Step-by-step explanation:

Using formula:

$T = 2 \pi \sqrt{\frac{l}{g}}$ ......[1]

where

T represents the Time period in second

l represents the length of the pendulum/

As per the statement:

Use the gravitational constant g = 9.8 m/s^2 , length of the simple pendulum(l) = 2 meters and $\pi = 3.14$

Substitute the given values we have;

$T = 2\cdot 3.14 \cdot \sqrt{\frac{2}{9.8}}$

⇒ $T = 6.28 \cdot \sqrt{\frac{1}{4.9}}=6.28 \cdot \frac{1}{2.21359436212}= \frac{6.28}{2.21359436212} = 2.83701481512$

Therefore, the period, in seconds to two decimal places is, 2.84 sec

8 0

4 years ago

HELP PLEASE! WILL GIVE BRAINLIEST TO THE BEST ANSWER!

RSB [31]

A:7 hope with helps :)

7 0

3 years ago

The figure below shows the ideal pattern of movement of a herd of cattle, with the arrows showing the movement of the handler as

geniusboy [140]

Based on the theory, the distance from the starting point to the return point = Arc length = 109.9 feet.

<h3>What is the Length of an Arc?</h3>

The arc length of a circle can be calculated with the radius and central angle using the arc length formula.

Arc length = ∅/360 × 2πr

Since the sector formed is a quarter circle, then ∅ = 90°.

Raidus (r) = 70 ft

Distance from the starting point to the return point = arc length.

Arc length = ∅/360 × 2πr = 90/360 × 2π(70)

Arc length = 109.9 feet

Therefore, based on the theory, the distance from the starting point to the return point = Arc length = 109.9 feet.

Learn more about the arc length on:

brainly.com/question/2005046

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2 years ago

asma owns $52000 in student loans for college. if the loan will be repaid in 5.5 years and the interest rate charged is 6.75% th

Ahat [919]

I=$52,000 R=6.75% T=5.5 years P=$19,305

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3 years ago

The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probabilit

Alik [6]

Answer:

a) The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b) We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean $\mu$ , standard deviation $\sigma$

a. Find the probability of a pregnancy lasting X days or longer.

The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b. If the length of pregnancy is in the lowest a%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

8 0

3 years ago