Ask question

Ask question

All categories

3 years ago

5

What are the coordinates of each point after quadrilateral ABCD is rotated 270° about the origin? Select numbers from the pull-d

own menus to complete the coordinates. Numbers may be used once, more than once, or not at all.

1 answer:

Mashcka [7]3 years ago

5 0

Answer:

140

Step-by-step explanation:

You might be interested in

Identify the type of function represented by f(x) = 4•3^x

SVEN [57.7K]

Since the variable x is at the exponent, this is an exponential function.

To decide whether an exponential function is a growing or decaying one, we have to look at the base of the exponent.

If the base is between 0 and 1, we have exponential decay

If the base is larger than 1, we have exponential growth.

In your case the base is 3, which is larger than 1, so you have exponential growth.

Thus, <u>option d</u> is your answer

7 0

2 years ago

Consider an experiment with a deck of 52 playing cards, in which there are 13 cards in each suit, two suits are black, and two s

lakkis [162]

Answer:

<u>P (E1) = 1/2 or 50%</u>

<u>P (E2) = 3/13 or 23%</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Number of playing cards = 52

Number of suits = 4

Number of cards per suit = 13

Number of black suits = 2

Number of red suits = 2

2. Suppose E1 = the outcome is a red card and E2 = the outcome is a face card (K, Q, J). Determine P(E1 or E2).

P (E1) = Number of red cards/Total of playing cards

P (E1) = 26/52 = 1/2 = 50%

P (E2) = Number of face cards/Total of playing cards

P (E2) = 12/52 = 3/13 = 23%

8 0

3 years ago

Read 3 more answers

There are 60 students and 13 teachers on a bus what is the ratio of students to teachers

mixer [17]

60 : 13

30 : 6.5

15 : 3.25

6 0

3 years ago

What's the flux of the vector field F(x,y,z) = (e^-y) i - (y) j + (x sinz) k across σ with outward orientation where σ is the po

emmasim [6.3K]

$\displaystyle\iint_\sigma\mathbf F\cdot\mathrm dS$
$\displaystyle\iint_\sigma\mathbf F\cdot\mathbf n\,\mathrm dS$
$\displaystyle\iint_\sigma\mathbf F\cdot\left(\frac{\mathbf r_u\times\mathbf r_v}{\|\mathbf r_u\times\mathbf r_v\|}\right)\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dA$
$\displaystyle\iint_\sigma\mathbf F\cdot(\mathbf r_u\times\mathbf r_v)\,\mathrm dA$

Since you want to find flux in the outward direction, you need to make sure that the normal vector points that way. You have

$\mathbf r_u=\dfrac\partial{\partial u}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=\mathbf k$
$\mathbf r_v=\dfrac\partial{\partial v}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=-2\sin v\,\mathbf i+\cos v\,\mathbf j$

The cross product is

$\mathbf r_u\times\mathbf r_v=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&1\\-2\sin v&\cos v&0\end{vmatrix}=-\cos v\,\mathbf i-2\sin v\,\mathbf j$

So, the flux is given by

$\displaystyle\iint_\sigma(e^{-\sin v}\,\mathbf i-\sin v\,\mathbf j+2\cos v\sin u\,\mathbf k)\cdot(\cos v\,\mathbf i+2\sin v\,\mathbf j)\,\mathrm dA$
$\displaystyle\int_0^5\int_0^{2\pi}(-e^{-\sin v}\cos v+2\sin^2v)\,\mathrm dv\,\mathrm du$
$\displaystyle-5\int_0^{2\pi}e^{-\sin v}\cos v\,\mathrm dv+10\int_0^{2\pi}\sin^2v\,\mathrm dv$
$\displaystyle5\int_0^0e^t\,\mathrm dt+5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv$

where $t=-\sin v$ in the first integral, and the half-angle identity is used in the second. The first integral vanishes, leaving you with

$\displaystyle5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv=5\left(v-\dfrac12\sin2v\right)\bigg|_{v=0}^{v=2\pi}=10\pi$

5 0

3 years ago

Solve the following equation for x.

Vaselesa [24]

Solve for x (isolate/get x by itself)

$\frac{1}{4}x-7=\frac{3}{8}x-5$ Add 5 on both sides

$\frac{1}{4}x-7+5=\frac{3}{8}x-5+5$

$\frac{1}{4}x-2=\frac{3}{8}x$ Subtract 1/4x on both sides

$\frac{1}{4}x-\frac{1}{4}x-2=\frac{3}{8}x-\frac{1}{4}x$

$-2=\frac{3}{8}x-\frac{1}{4}x$ Make the denominators the same of the fractions in order to combine them. Multiply 2 to the top and bottom of 1/4x

$-2=\frac{3}{8}x-\frac{2}{8}x$

$-2=\frac{1}{8}x$ Multiply 8 on both sides

$-2(8)=(8)\frac{1}{8}x$

-16 = x

7 0

3 years ago