If a= 5^99 x 2^98 and b= 5^72 x 4^38 show ab has 172 digits when written as a ordinary number
1 answer:
Step-by-step explanation:
ab
= (5⁹⁹ * 2⁹⁸) * (5⁷² * 4³⁸)
= 2⁹⁸ * 2⁷⁶ * 5⁹⁹ * 5⁷²
= 2¹⁷⁴ * 5¹⁷¹
= 2³ * (2¹⁷¹ * 5¹⁷¹).
The 2¹⁷¹ * 5¹⁷¹ will give 171 ending zeroes as 2 * 5 = 10.
And there is a 8 infront as 2³ = 8.
Hence altogether there are 171 + 1 = 172 digits.
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Answer:
the third one/second one
Step-by-step explanation:
Answer:Let the amount invested in each be
A and B
A+B=5000
0.1A+0.15B=630
0.1(5000-B)+0.15B=630
500-0.1B+0.15B=630
0.05B=130
B=2600
A=2400
Step-by-step explanation:
The answer would be Associative Property.
Hope this helps you =)
Ok then um so ya ok thx for the points though
P = 2(L + W)
P = 180
W = L - 24
now we sub
180 = 2(L + L - 24)
180 = 2(2L - 24)
180 = 4L - 48
180 + 48 = 4L
228 = 4L
228/4 = L
57 = L
W = L - 24
W = 57 - 24
W = 33
so ur length (L) = 57 ft and ur width (W) = 33 ft
